Please help me it’s emergency please

Mathematics

2 answers:

Darya [45]3 years ago

6 0

Answer:

The other person is correct he should get brainliest!

Hope this helps!

PolarNik [594]3 years ago

4 0

Answer:

-17x

Step-by-step explanation:

(2x^3 - x^2) - (3x^3 - 2x^2)

(8x - 2x) - (27x - 4x)

6x - 23x

-17x

(I haven't seen many questions like this before, but I think that this may be the answer.)

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What is a the sign of a x b (A) positive (B) negative (C) zero

Blizzard [7]

Answer:

I think it would be negative. So, B

Step-by-step explanation:

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5 0

4 years ago

student randomly receive 1 of 4 versions(A, B, C, D) of a math test. What is the probability that at least 3 of the 5 student te

alexdok [17]

Answer:

1.2%

Step-by-step explanation:

We are given that the students receive different versions of the math namely A, B, C and D.

So, the probability that a student receives version A = $\frac{1}{4}$ .

Thus, the probability that the student does not receive version A = $1-\frac{1}{4}$ = $\frac{3}{4}$ .

So, the possibilities that at-least 3 out of 5 students receive version A are,

1) 3 receives version A and 2 does not receive version A

2) 4 receives version A and 1 does not receive version A

3) All 5 students receive version A

Then the probability that at-least 3 out of 5 students receive version A is given by,

$\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{3}{4}\times \frac{3}{4}$ + $\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{3}{4}$ + $\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}$