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3 years ago

How do I solve question 1

Mathematics

1 answer:

vitfil [10]3 years ago

5 0

Well it says t= 5 so you literally put 5 in for t into the equation to get y

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Find the area and perimeter of the figure. I need help on this

kotykmax [81]

Answer:

area=38cm²

perimeter=34cm

Step-by-step explanation:

I found three shapes and got

4·2=8

3·3=9

9·3=21

8+9+21=38cm²

5+6+9+4+3+2+2+3=34

6 0

3 years ago

Read 2 more answers

Ten thousand raffle tickets are sold for $1 each. One first prize of $2000, 4 second prizes of $700 each, and 8 third prizes of

Nina [5.8K]

Answer:

72 cents.

Step-by-step explanation:

The expected winnings is the amount times the probability that you will get that amount.

2,000 * (1/10,000) = 2,000 / 10,000 = 2 / 10 = 0.2.

700 * (4 / 10,000) = 2,800 / 10,000 = 28 / 100 = 0.28.

300 * (8 / 10,000) = 2,400 / 10,000 = 24 / 100 = 0.24.

0.2 + 0.28 + 0.24 = 0.72.

Hope this helps!

4 0

3 years ago

Helppppp aceeee/expertttsss quickkkk

baherus [9]

Point A would be the answer because...
The distance between A and C is point B, which doesn't land on -2
Point A lands on -2.
The distance between A and D would be points B and C, both don't land on -2.
The opposite of -2 would be positive 2 and thats point D.
I hope this helps love.

8 0

3 years ago

Helppppppppppppppppppp

zloy xaker [14]

Answer: T= 1 and I’m not sure if 6t = 6

6 0

3 years ago

Given the equation 5x − 4 = –2(3x + 2), solve for the variable. Explain each step and justify your process.

blagie [28]

A.
$5x-4=-2(3x+2) \ \ \ \ \ \ \ \ \ |\hbox{expand the bracket} \\
5x-4=-2 \times 3x-2 \times 2 \\
5x-4=-6x-4 \ \ \ \ \ \ \ \ \ \ \ \ \ |\hbox{add 6x to both sides} \\
11x-4=-4 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\hbox{add 4 to both sides} \\
11x=0 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\hbox{divide both sides by 11} \\
x=0$

B.
$3(2x-4)=5x-1 \\
6x-12=5x-1 \\
\boxed{11x-12=-1} \Leftarrow \hbox{the first mistake} \\
11x=11 \\
\boxed{x=11} \Leftarrow \hbox{the second mistake}$

Megan's solution isn't correct.
The first mistake: she subtracted 5x from the right-hand side of the equation, but added 5x to the left-hand side.
The second mistake: she divided the right-hand side of the equation by 11, but didn't divide the left-hand side.

The correct solution:
$3(2x-4)=5x-1 \ \ \ \ \ \ \ \ \ \ \ |\hbox{expand the bracket} \\
3 \times 2x+3 \times (-4)=5x-1 \\ 6x-12=5x-1 \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\hbox{subtract 5x from both sides} \\
x-12=-1 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\hbox{add 12 to both sides} \\
x=11$

3 0

3 years ago