To evaluate the probability that a randomly selected day will be between 28 and 34 minutes we proceed as follows:
P(28<x<34)
First we evaluate the z-score for the above values:
z=(x-σ)/μ
μ=26.7
σ=5.1
when:
x=28
z=(28-26.7)/5.1
z=0.26
P(z<0.26)=0.6026
when x=34
z=(34-26.7)/5.1
z=1.43
P(z<1.43)=0.9236
hence:
P(28<x<34)=0.9236-0.6026=0.321~32.1%
The correct answer is C.
You can tell this by factoring the equation to get the zeros. To start, pull out the greatest common factor.
f(x) = x^4 + x^3 - 2x^2
Since each term has at least x^2, we can factor it out.
f(x) = x^2(x^2 + x - 2)
Now we can factor the inside by looking for factors of the constant, which is 2, that add up to the coefficient of x. 2 and -1 both add up to 1 and multiply to -2. So, we place these two numbers in parenthesis with an x.
f(x) = x^2(x + 2)(x - 1)
Now we can also separate the x^2 into 2 x's.
f(x) = (x)(x)(x + 2)(x - 1)
To find the zeros, we need to set them all equal to 0
x = 0
x = 0
x + 2 = 0
x = -2
x - 1 = 0
x = 1
Since there are two 0's, we know the graph just touches there. Since there are 1 of the other two numbers, we know that it crosses there.
Answer: 99.7%
Step-by-step explanation:
Edg 2020
Answer:
(6x+5)(4x−1)
Step-by-step explanation:
24x² + 14x - 5 Factor the expression
(6x+5)(4x−1) Double check the answer by FOILing
24x² - 6x + 20x - 5 Combine like terms
24x² + 14x - 5 This answer does work
If this answer is correct, please make me Brainliest!
Answer:
480 different sandwiches
Step-by-step explanation:
To find how many sandwiches can be made, we need to find the number of possibilities for each choice: bread, protein, cheese, vegetables.
Bread: 3 types -> combination of 3 choose 1 -> 3
Protein: 4 types -> combination of 4 choose 1 -> 4
Cheese: 4 types -> combination of 4 choose 1 -> 4
Vegetables: 5 types -> combination of 5 choose 2 -> 5!/(3!*2!) = 5*4/2 = 10
So the number of different sandwiches is:
3 * 4 * 4 * 10 = 480
