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Zinaida [17]
3 years ago
11

How do I solve 3 1/2r = 28

Mathematics
2 answers:
lozanna [386]3 years ago
7 0
3 1/2r=28
7/2r=28
r=(28/1)(2/7)
r=8
juin [17]3 years ago
6 0
You divide 3 1/2 on both sides, which means your answer is r = 28 divided by 3 1/2, or 8.
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3 years ago
Which terms could be used as the first term of the expression below to create a polynomial written in standard form? Select five
Alina [70]

Answer:

3r⁴s⁵

- r⁴s⁶

- 6rs⁵

Step-by-step explanation:

1) The expression given is:

+ 8r²s⁴ – 3r³s³

2) The choices given are:

s⁵

3r⁴s⁵

- r⁴s⁶

- 6rs⁵

1) A polynomial written in standard form has the terms ordered in decreasing order.

For example, 4x⁵ + 8x⁴ + 3x² + 27

2) The given polynomial has degree 6: + 8r²s⁴ – 3r³s³, and it can be ordered respect any of the two variables either r or s.

3)  Adding a new term as first term needs to have degree equal or greater than 6.

So, the candidates from the list are: 3r⁴s⁵, - r⁴s⁶,- 6rs⁵

4) If you use 3r⁴s⁵, the polynomial in standard form would be:

3r⁴s⁵ – 3r³s³ + 8r²s⁴ (as you see the degree of r is decreasing from left to right).

5) If you use - r⁴s⁶, the polynomial in standard form would be:

- r⁴s⁶ – 3r³s³ + 8r²s⁴ (as you see, the degree of r decreases from left to right)

6) If you use - 6rs⁵, the polynomial in standard form would be

- 6 rs⁵– 3r³s³ + 8r²s⁴ (as you see the degree of s is decreasing from left to right).

7) You cannot use s⁵ as first term because its degree is less than 6.

3 0
3 years ago
Read 2 more answers
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