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2 years ago

The second step in the process for factoring the trinomial o2 5x 36 is to

1 answer:

3 0

I would have to sy that the factor of the thm. should be the factors of 36, and then test each value to see the results in 0

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(57x2:3)+32x450-[39-(4+2):2[+8=

tigry1 [53]

Answer:

57×2/3+32×450-[39-4+2]/2+8

57×2/3+32×450-(39-6/2)+8

57×2/3+32×450-36+8

57×2/3+14400-28

57×2/3+14372

38+14372

14410

8 0

2 years ago

Find the missing side length, and enter your answer in the box below. If

Savatey [412]

The missing side length is c = 25 units.

Step-by-step explanation:

Step 1:

The given triangle has a 24 unit long adjacent side and a 7 unit long opposite side.

As we have two sides of the triangle, we can solve for the length of the other side by using Pythagoras' theorem.

The length of the hypotenuse is given as c units.

Step 2:

According to Pythagoras theorem,

$c^{2} = 24^{2} + 7^{2} = 576 + 49.$

$c^{2} = 625, c = 25.$

So the missing length, c of the given triangle is 25 units.

8 0

2 years ago

What are the potential solutions to the equation 2ln(x+3)=0

skad [1K]

$2\ln(x+3)=0\implies \ln(x+3)^2=0\implies e^{\ln(x+3)^2}=e^0\implies (x+3)^2=1$

Expanding the left side gives

$x^2+6x+9=1\implies x^2+6x+8=0\implies (x+4)(x+2)=0$

which gives two solutions, $x=-4$ and $x=-2$ . But if $x=-4$ , then $\ln(x+3)=\ln(-1)$ , but this number isn't real, so $x=-4$ is an extraneous solution. Meanwhile if $x=-2$ , you get $\ln(-2+3)=\ln1=0$ , so this solution is correct.

"Potential solutions" might refer to both possibilities, but there is only one actual (real) solution.

4 0

3 years ago

Read 2 more answers

Answers: <br> a) 74<br> b) 108<br> c)49<br> d)51

lisabon 2012 [21]

Answer:

Step-by-step explanation:

sum of exterior angles = 360

64 + 60 + 69 + 42 + x + x +23 = 360

2x + 258 = 360

2x = 360 - 258

2x = 102