Answer:
Therefore they are 734.106 miles apart.
Step-by-step explanation:
Given that ,
Two ships have a harbor together. The angle between two ships is 135°40'. Each of two ships travel 402 miles.
It forms a isosceles triangle whose two sides are 402 miles and one angle is 135°40'. Since it is isosceles triangle then other two angles of the triangle is equal.
Let ∠B= 135°40', and AB = 402 miles , BC = 402 miles
Then the distance between the ships = AC
We know
The sum of all angles = 180°
⇒∠A+∠B+∠C=180°
⇒∠A+135°40'+∠C=180°
⇒2∠A= 180°- 135°40' [ since ∠A=∠C]
⇒2∠A=44°60'
⇒∠A= 22°30'
Again we know that,
Taking last two ratio,
Putting the value of BC , AC ,∠A,∠B
≈734.106 miles
Therefore they are 734.106 miles apart.
Answer:
65°
Step-by-step explanation:
Radii CA and CB are perpendicular to tangent lines AT and BT, so
Since angle BAT is equal to 65°, angle CAB has measure
Consider triangle ACB. This triangle is isosceles, because CA=CB as radii of the circle. Two angles adjacent to the base are congruent, thus
The sum of the measures of all interior angles in triangle is always 180°, so
Angle ACB is central angle subtended on the minor arc AB, angle APB is inscribed angle subtended on the same minor arc AB. The measure of inscribed angle is half the measure of central angle subtended on the same arc, so
Answer:
1.25 hours or 1 hour and 15 minutes
Step-by-step explanation:
12:45 - 12:30 = :15
15 minutes equates to 1/5 of the rides
So, we multiply 15 by 5 to find the total time taken to ride all the rides.
15 x 5 = 75
75/60 = 1.25
It would take him 1.25 hours to ride all the rides at the carnival or 1 hour and 15 minutes.
collinear points are points in the same line, like
●-----------------●------------------------------------------●
and the line will always be contained by a plane, so since the line is in a plane, all points in it will also be in the same plane, and therefore be coplanar.
