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Inessa05 [86]
3 years ago
13

Solve 6^(4x+1)=5^(x-3) for x

Mathematics
2 answers:
AleksandrR [38]3 years ago
8 0

6^{4x+1}=5^{x-3}\\\\\log6^{4x+1}=\log5^{x-3}\\\\(4x+1)\log 6=(x-3)\log 5\\\\(4x+1)\log 6-(x-3)\log 5=0\\\\4x\log 6+\log 6-x\log 5+3\log 5=0\\\\4x\log 6-x\log 5 = -3\log 5-\log 6\\\\x(4\log 6-\log 5) = -3\log 5-\log 6\\\\x=\dfrac{-3\log 5-\log 6}{4\log 6-\log 5}\\\\x=\dfrac{3\log 5+\log 6}{\log 5-4\log 6}

myrzilka [38]3 years ago
7 0

Answer: The answer is C

Step-by-step explanation:

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step by step explanation:
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A hockey player knows that the two goal posts of a hockey net are 1.83 meters apart. The player tries to score a goal by shootin
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The distance the player is from the right post is = 5.1 meters

<h3>Calculation of distance using Pythagorean theorem</h3>

The Pythagorean theorem states that the square of the length of the hypotenuse of a right triangle equals the sum of the squares of the lengths of the other two sides.

Formula for the Pythagorean theorem =

a²= b²+c²

From the diagram given,

The hypotenuse (a) = x²

b= 1.82²

c = 4.8²

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2 years ago
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3 years ago
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Read 2 more answers
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Answer:

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Step-by-step explanation:

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4 0
3 years ago
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