4 years ago

Solve 6^(4x+1)=5^(x-3) for x

2 answers:

8 0

$6^{4x+1}=5^{x-3}\\\\\log6^{4x+1}=\log5^{x-3}\\\\(4x+1)\log 6=(x-3)\log 5\\\\(4x+1)\log 6-(x-3)\log 5=0\\\\4x\log 6+\log 6-x\log 5+3\log 5=0\\\\4x\log 6-x\log 5 = -3\log 5-\log 6\\\\x(4\log 6-\log 5) = -3\log 5-\log 6\\\\x=\dfrac{-3\log 5-\log 6}{4\log 6-\log 5}\\\\x=\dfrac{3\log 5+\log 6}{\log 5-4\log 6}$

myrzilka [38]3 years ago

7 0

Answer: The answer is C

Step-by-step explanation:

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An unfair coin is twice as likely to land "Heads" as "Tails". If the coin is tossed twice, what is the probability that it will

Ierofanga [76]

The probability of getting two heads on two coin tosses is 0.5 x 0.5 or 0.25. A visual representation of the toss of two coins. The Product Rule is evident from the visual representation of all possible outcomes of tossing two coins shown above.

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2 years ago

HELP PLEASE LOOK AT PICTURE

solniwko [45]

Answer:

It decreases.

Step-by-step explanation:

10 / d

Lets say that it was 10 / 40, which is 10 divided by 40, 0.25.

Now, it has increased to twice the amount of that.

1 / 80, 10 divided by 80, which is 0.125

So, it decreases.