Answer:
Step-by-step explanation:
By the Intersecting secants theorem, we know that:
Then, substituting, we get:
Now we need to expand the expression:
Simplifying, we get that the value of "x" is:
Y=x^2-5, solve for x
y+5=x^2
x=√(y+5) so
f^-1(x)=√(y+5)
Answer:
X= 20
Step-by-step explanation:
Since the they are both interior angles they can be set equal to each other.
Option B
Trevor isn't correct because -2i must also be a root
<em><u>Solution:</u></em>
For the polynomial with roots -7, 2i and 7 their roots can be,
1. ) Real roots
2.) Imaginary roots
The real roots are: -7 and +7
The imaginary root given is: 2i
The imaginary roots come from the square root. So they will be in form of
Therefore,
For f(x) with roots -7 and +7 and we have,
Fundamental Theorem of Algebra states that a polynomial will have exactly as many roots as its degree (the degree is the highest exponent of the polynomial).
So for f(x) with 4 roots, degree of f(x) is 4
So option B is correct. Trevor is not correct because –2i must also be a root.
Answer:
The complement is 53 and the supplement is 143
Step-by-step explanation:
Two complementary angles add to 90
PQR and x = 90
37+x = 90
Subtract 37 from each side
37-37 +x =90-37
x = 53
The complement is 53
Two supplementary angles add to 180 degrees
PQR and x = 180
37+x = 180
Subtract 37 from each side
37-37 +x= 180-37
x = 143
The supplement is 143