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3 years ago

6

PLEASE HURRY

1 answer:

KIM [24]3 years ago

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Find the value of x. Round to the nearest tenth of the right triangle. hypotenuse is 25, bottom leg is 13, and angle is x

Verizon [17]

OK so we know that the other side is 12 because the right triangle has to have two sides that add up to the hypotenuse, and I believe it gives you the answer in the question because you are trying to find x which it says x is the angle, and since its a right triangle, it would be 90°

7 0

2 years ago

5/6 plus blank equals to 5/2

Tju [1.3M]

Answer:

$\frac{5}{3}$

Step-by-step explanation:

let blank be O

$\frac{5}{6} +O=\frac{5}{2} \\$

$O=\frac{5}{2} -\frac{5}{6} =\frac{15}{6} -\frac{5}{6} =\frac{10}{6} =\frac{5}{3}$

8 0

2 years ago

Identify the correct corresponding parts

andrey2020 [161]

Answer:

The correct corresponding part is;

$\overline {CB}$ ≅ $\overline {CD}$

Step-by-step explanation:

The information given symbolically in the diagram are;

ΔCAB is congruent to ΔCED (ΔCAB ≅ ΔCED)

Segment $\overline {CA}$ is congruent to $\overline {CE}$ ( $\overline {CA}$ ≅ $\overline {CE}$ )

Segment $\overline {CB}$ is congruent to $\overline {CD}$ ( $\overline {CB}$ ≅ $\overline {CD}$ )

From which, we have;

∠A ≅ ∠E by Congruent Parts of Congruent Triangles are Congruent (CPCTC)

∠B ≅ ∠D by CPCTC

Segment $\overline {AB}$ is congruent to $\overline {DE}$ ( $\overline {AB}$ ≅ $\overline {DE}$ ) by CPCTC

Segment $\overline {AE}$ bisects $\overline {BD}$

Segment $\overline {BD}$ bisects $\overline {AE}$

Therefore, the correct option is $\overline {CB}$ ≅ $\overline {CD}$

3 0

2 years ago

(Will give brainiest)<br><br>5y - x = 10<br><br>4x - 4y = 1<br><br>12 = 6x + 3y

kow [346]

Is there any answer choices to what we are looking for?

7 0

3 years ago

According to the Bureau of Labor Statistics, students who have an after-school job spend an average of 42 fewer minutes per day

IgorLugansk [536]

Answer:

126 hrs

Step-by-step explanation:

-Given the school year has 180 days and the non-working student spends 42 minutes more than the working student.

-The total time during the school year is calculated as;

$Total Time=Time/day \times No \ of \ Days\\\\=42\ minutes \times 180\\\\=7560\ minutes$

We convert our calculated time in hour(1hr=60 minutes):

$=\frac{7560\ mins}{60\ mins}\\\\=126\ hrs$

Hence, the average non-working spends an average of 126 hrs that the working student.

4 0

2 years ago