The number of students spent time useing electronic devices is ? Times the number of hours spent playing sports

Use a scientific calculator to evaluate ln 26 (round to the nearest ten-thousandth).

tamaranim1 [39]

Ln 26 = 3.2581 to the nearest ten thousandth

3 0

3 years ago

The function = 3describes the volume of a cube, , in cubic inches, whose length, width, and height each measure inches. Find the

kolezko [41]

The correct structure of the question is as follows:

The function f(x) = x^3 describes a cube's volume, f(x) in cubic inches, whose length, width, and height each measures x inches. If x is changing, find the (instantaneous) rate of change of the volume with respect to x at the moment when x = 3 inches.

Answer:

Step-by-step explanation:

Given that:

f(x) = x^3

Then;

V = x^3

The rate whereby V is changing with respect to time is can be determined by taking the differentiation of V

dV/dx = 3x^2

Now, at the moment when x = 3;

dV/dx = 3(3)^2

dV/dx = 3(9)

dV/dx = 27 cubic inch per inch

Suppose it is at the moment when x = 9

Then;

dV/dx = 3(9)^2

dV/dx = 3(81)

dV/dx = 243 cubic inch per inch

6 0

2 years ago

Eathan ran 11 miles in 2 hours. what is the unit rate of miles to hours

spayn [35]

Answer:

5.5:1

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Mitchell walked 5/12 of a mile in 1/2 of an hour. At this rate, how far could Mitchell walk in 1 hour?

vovangra [49]

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$2 \times \frac{1}{2} hour = 1hour \\$

Thus ;

$2 \times \frac{5}{12} \: \: miles = \frac{10}{12} \: \: miles = \frac{5}{6} \: \: miles \\$

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6 0

2 years ago

Read 2 more answers

Please answer question three and four if you can :)<br> Show full working out ty;)

nikklg [1K]

Step-by-step explanation:

3

Let D be the mid point of side BC, [B(2, - 1), C(5, 2)].

Therefore, by mid-point formula:

$D = ( \frac{2 + 5}{2}, \: \: \frac{ - 1 + 2}{2} ) = ( \frac{7}{2}, \: \: \frac{ 1}{2} ) \\ \therefore D= (3.5, \: \: 0.5) \\ \& \: A=(-1,\:\:4)...(given) \\\\ now \: by \: distance \: formula \\ \\ Length \: of \: segment \: AD \\ = \sqrt{( - 1 - 3.5)^{2} + {(4 - 0.5)}^{2} } \\ = \sqrt{(4.5)^{2} + {(3.5)}^{2} } \\ = \sqrt{20.25 + 12.25 } \\ = \sqrt{32.5} \\ \red{ \boxed{\therefore Length \: of \: segment \: AD = 5.7 \: units}}$

4 (a)

Equation of line AB[A(2, 1), B(-2, - 11)] in two point form is given as:

$\frac{y-y_1}{y_1-y_2} =\frac{x-x_1}{x_1 - x_2} \\\\\therefore \frac{y-1}{1-(-11)} =\frac{x-2}{2 - (-2) } \\\\\therefore \frac{y-1}{1+11} =\frac{x-2}{2 +2} \\\\\therefore \frac{y-1}{12} =\frac{x-2}{4} \\\\\therefore \frac{y-1}{3} =\frac{x-2}{1} \\\\\therefore y-1= 3(x - 2)\\\\\therefore y= 3x - 6+1\\\\\therefore y= 3x - 5\\\\ \huge \purple {\boxed {\therefore 3x - y-5=0}} \\$

is the equation of line AB.

Now we have to check whether C(4, 7) lie on line AB or not.

Let us substitute x = 4 & y = 7 on the Left hand side of equation of line AB and if it gives us 0, then C lies on the line.

$LHS = 3x - y-5\\=3\times 4-7-5\\= 12-12\\=0\\= RHS$

Hence, point C (4, 7) lie on the straight line AB.

4(b)

Like we did in 4(a), first find the equation of line AB and then substitute the coordinates of point C in equation and if they satisfy the equation, then all the three points lie on the straight line.

4 0

3 years ago