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Oksana_A [137]
1 year ago
13

Can someone please help me

Mathematics
1 answer:
DedPeter [7]1 year ago
5 0

Answer:

6

Step-by-step explanation:

Perimeter = 2l + 2w

48 = 2(18) + 2(w)

48 = 36 + 2w

12 = 2w

w = 6

<em>Could you please give me brainliest for this? Thank you!</em>

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Describe the credit process, using five vocabulary terms from the chapter.
Mandarinka [93]

Answer:

The answer is a and e

Step-by-step explanation:

7 0
3 years ago
Find the percent of change. Round to the nearest percent.
katovenus [111]

Answer:

<u> -54.5%</u>

Step-by-step explanation:

You will have to use this formula

\frac{new value-oldvalue}{oldvalue}

When substituted in you have \frac{30-66}{66}

30-66=-36

-36/66= -0.54 (54 repeating)

Then you have to convert this into a percentage, -54.54(repeating) percent

To the nearest hundredth you would round down to<u> -54.5%</u>.

It is a Decrease because it is negatated.

8 0
3 years ago
Instructions: Use the ratio of a 30-60-90 triangle to solve for the variables.
Pepsi [2]

Answer:

x=20

y=10\,\sqrt{3}

Step-by-step explanation:

In the triangle we have the following trigonometric equations:

tan(60^o)=\frac{opposite}{adjacent} \\\sqrt{3} =\frac{y}{10} \\y=10\,\sqrt{3}

and also:

cos(60^o)=\frac{adjacent}{hypotenuse}\\\frac{1}{2} =\frac{10}{x}\\x=20

8 0
3 years ago
The population of deer in a state park can be predicted by the expression 106(1.087)t, where t is the number of years since 2010
Arturiano [62]

Answer:

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Step-by-step explanation:

8 0
4 years ago
The USDA conducted tests for salmonella in produce grown in California. In an independent sample of 252 cultures obtained from w
Marat540 [252]

Answer:

 The decision rule is  

Fail to reject the null hypothesis

  The conclusion is  

There no sufficient evidence to show that the proportion of salmonella in the region’s water differs from the proportion of salmonella in the region’s wildlife

Step-by-step explanation:

From the question we are told that

   The first  sample size is n_1   =  252

    The number that tested positive is  k_1  =  18

     The second sample size is  n_2   =  476

     The number that  tested positive is  k_2 =  20

     The level of significance is  \alpha  = 0.01

Generally the first sample proportion is mathematically represented as

      \^ p _1 =  \frac{k_1 }{ n_1 }

=>    \^ p _1 =  \frac{18 }{ 252 }

=>    \^ p _1 = 0.071

Generally the second sample proportion is mathematically represented as

      \^ p _2 =  \frac{k_2 }{ n_2 }

=>    \^ p _2 =  \frac{20 }{ 476}

=>    \^ p _2 = 0.042

The  null hypothesis is            H_o  :  p_1 - p_2 = 0

The alternative hypothesis is  H_a :  p_1 - p_2 \ne 0

Generally the test statistics is mathematically represented

       z =  \frac{ \^ p_1 - \^ p_2  -  ( p_ 1 - p_2 )}{ \sqrt{\frac{\^ p_1 (1-\^ p_1)}{ n_1  } + \frac{\^ p_2 (1-\^ p_2)}{ n_2  }  } }

=>    z =  \frac{ 0.071 - 0.042  - 0 }{ \sqrt{\frac{0.071  (1-0.071)}{  252  } + \frac{0.042 (1-\^ 0.042)}{ 476  }  } }

=>    z =  1.56

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        P(Z >  1.56 ) =0.05938

Generally the p-value is mathematically represented as

         p-value =  2 * P(Z >  1.56 )

=>      p-value = 2 *  0.05938

=>      p-value = 0.1188

From the value obtained we see that   p-value  >  \alpha hence

  The decision rule is  

Fail to reject the null hypothesis

  The conclusion is  

There no sufficient evidence to show that the proportion of salmonella in the region’s water differs from the proportion of salmonella in the region’s wildlife

 

5 0
3 years ago
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