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Vikentia [17]
4 years ago
9

How do you compute unit rates associates with ratios and fractions?

Mathematics
1 answer:
Crazy boy [7]4 years ago
5 0
<span>Compute unit rates associated with ratios of fractions, including ratios of lengths, areas and other quantities measured in like or different units. For example, if a person walks 1/2 mile in each 1/4 hour, compute the unit rate as the complex fraction 1/2/1/4 miles per hour, equivalently 2 miles per hour. ... hope this helps.</span>
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it had made of two lines including an angle...

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Find the ratio of ruppees 5 to 50 paise​
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5:50 —> divide by 5 so it becomes 1:10
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3 years ago
A person walks 1/5 mile in 1/15 hour the person speed is what miles per hour
andrey2020 [161]

Answer:

(1/5 mi) / (1/15 hr) = 1/5 * 15/1 = 3 mi/hr

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
I. In a shipment of 300 connecting rods, the mean tensile strength is found to be 45 kpsi and has a standard deviation of 5 kpsi
CaHeK987 [17]

Answer:

a) Between 39 and 40 rods can be expected to have a strength less than 39.4 kpsi.

b) 260 rods are expected to have a strength between 39.4 and 60 kpsi

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 45, \sigma = 5

(a) Assuming a normal distribution, how many rods can be expected to have a strength less than 39.4 kpsi?

The percentage of rods with a stength less than 39.4 is the pvalue of Z when X = 39.4. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{39.4 - 45}{5}

Z = -1.12

Z = -1.12 has a pvalue of 0.1314

13.14% of rods have a strength less than 39.4 kpsi.

Out of 300

0.1314*300 = 39.42

Between 39 and 40 rods can be expected to have a strength less than 39.4 kpsi.

(b) How many are expected to have a strength between 39.4 and 60 kpsi?

The percentage of rods with a stength in this interval is the pvalue of Z when X = 60 subtracted by the pvalue of Z when X = 39.4. So

X = 60

Z = \frac{X - \mu}{\sigma}

Z = \frac{60 - 45}{5}

Z = 3

Z = 3 has a pvalue of 0.9987

X = 39.4

Z = \frac{X - \mu}{\sigma}

Z = \frac{39.4 - 45}{5}

Z = -1.12

Z = -1.12 has a pvalue of 0.1314

0.9987 - 0.1314 = 0.8673

86.73% of the rods are expected to have a strength between 39.4 and 60 kpsi

Out of 300

0.8673*300 = 260

260 rods are expected to have a strength between 39.4 and 60 kpsi

4 0
4 years ago
Can somebody help me first answer gets brainiest pls help
damaskus [11]
Answer: I believe the answer is 216 Square units.

Explanation:
1. Cut the shape in half. Now you have a square and a triangular shape.

2. The square is 12 inches on all four sides. 12 • 12 = 144. 144 is the area for the square.

3. Now, the triangular shape. The bottom of the shape is 12 because we divided the total 24 in half with the square. The left side (the longer side) of the shape is also 12 because it is parallel to the square with 12 as the same measurement. The right side (the shorter side) of the shape is 6 because it's half the size of the square’s length. The length of the top of the shape is also 12 because it is half of the square’s width of 24.

4. Now that we have found the measurements of the triangular shape, we can multiply (length • width) and add. The square is 144 units (12•12=144) and the triangular shape is 72 (12•6=72). 144 + 72= 216.

I hope this helps! :)
6 0
3 years ago
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