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2 years ago

If d(4)= 68. thus, joe travels 68 mi in 4 hours. then how much mi does joe travel in 45 minutes

Mathematics

1 answer:

zhuklara [117]2 years ago

3 0

Given that, Joe travels 68 mi in 4 hours, the number of miles Joe will travel in 45 minutes is 12.75.

<h3>How many miles did joe travel in 45 minutes?</h3>

Given that;

Joe travels 68 miles in 4 hours
joe travel x miles in 45 minutes

First, we convert 4 hours to minutes: 4 × 60 = 240 minutes

Now,

Joe travels 68 miles in 240 minutes

Joe will travel x miles in 45 minutes

We have;

x × 240 = 68 × 45

x × 240 = 3060

x = 3060 / 240

x = 12.75 miles.

Given that, Joe travels 68 mi in 4 hours, the number of miles Joe will travel in 45 minutes is 12.75.

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Step-by-step explanation:

1/4 (g + 2) = 8

g + 2 = 8 (4)

g = 32 - 2

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Need help with question 11 and 12

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Answer:

11. your choices are correct

12. 132°

Step-by-step explanation:

11. The given equations can be (re)written to slope-intercept form. Only those lines with a slope of 2 will be parallel to the given line.

A: y = 2x -8 . . . . . slope = 2, an answer

B: y = -2x +1 . . . . . slope = -2, not an answer

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E: y = -2x -9 . . . . . slope = -2, not an answer

12. The marked angles are supplementary, so ...

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3 years ago

Suppose both factors in a multiplication problem are multiples of 10. Why might the number of zeroes in the product be different

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Answer:

Multiplying factors whose products are multiples of 10 add to the number of zeros when factors are multiplied as multiples of 10s.

Step-by-step explanation:

Let the first five multiples of ten be

10*1= 10

10*2= 20

10*3=30

10*4=40

10*5= 50

Suppose we chose 20 and 50.

Now multiplying 20 with 50 we get

20*50= 1000

IF we count the total number of zeros in the factors ( 20 and 50) they are 2.

But the number of zeros in the product (1000) are 3.

This is because when we multiply 2 with 5 we get 10 which adds to the existing number of zeros ( i.e 2) and we get a total of 3 zeros.

And multiplying 10 with 50 we get

10*50= 500

IF we count the total number of zeros in the factors ( 10 and 50) they are 2.

But the number of zeros in the product (500) are also 2.

This is because when we multiply 1 with 5 we get 5 which does not add to the existing number of zeros ( i.e 2) and the total number of zeros remain the same.

Similarly multiplying 20 with 30 we get

20*30= 600

IF we count the total number of zeros in the factors ( 20 and 30) they are 2.

But the number of zeros in the product (600) are also 2.

This is because when we multiply 2 with 3 we get 6 which does not have a zero and the total number of zeros remain the same as in the factors.

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3 years ago

Suppose the probability of an IRS audit is 1.5 percent for U.S. taxpayers who file form 1040 and who earned $100,000 or more.

sp2606 [1]

Answer:

(A) The odds that the taxpayer will be audited is approximately 0.015.

(B) The odds against these taxpayer being audited is approximately 65.67.

Step-by-step explanation:

The complete question is:

Suppose the probability of an IRS audit is 1.5 percent for U.S. taxpayers who file form 1040 and who earned $100,000 or more.

A. What are the odds that the taxpayer will be audited?

B. What are the odds against such tax payer being audited?

Solution:

The proportion of U.S. taxpayers who were audited is:

P (A) = 0.015

Then the proportion of U.S. taxpayers who were not audited will be:

P (A') = 1 - P (A)

= 1 - 0.015

= 0.985

(A)

Compute the odds that the taxpayer will be audited as follows:

$\text{Odds of being Audited}=\frac{P(A)}{P(A')}$

$=\frac{0.015}{0.985}\\\\=\frac{3}{197}\\\\=0.015228\\\\\approx 0.015$

Thus, the odds that the taxpayer will be audited is approximately 0.015.

(B)

Compute the odds against these taxpayer being audited as follows:

$\text{Odds against Audited}=\frac{P(A')}{P(A)}$

$=\frac{0.985}{0.015}\\\\=\frac{3}{197}\\\\=65.666667\\\\\approx 65.67$

Thus, the odds against these taxpayer being audited is approximately 65.67.

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3 years ago