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3 years ago

1.4 metres is the same one of which one: 1400mm

1 answer:

7 0

$m-meter\\mm-millimeter\\cm-centimeter\\\\1m=1,000mm\ \ \ (mili=0.001\ of\ some\ unit)\\1m=100cm\ (centi=0.01\ of\ some\ unit)\\1.4m=1.4\times1,000mm=\huge\boxed{1,400mm}\\\\1.4m=1.4\times100cm=\huge\boxed{140cm}$

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Which is greater 7/10 or 3/5

prisoha [69]

7/10 because when you make the denominators the same (10) you do same thing to the 3 making it a six and 7 is greater then 6

8 0

3 years ago

What is the value of in 43 to four decimal places?

Leviafan [203]

This would be 43.0000, because you can continue to add 0's after the decimal place without changing the actual value of the number.

6 0

3 years ago

Gerald’s bucket lost a total of 8/5 in. of water when the hot summer sun came out. He estimated that he lost 2/15 in. an hour. H

Dahasolnce [82]

Answer:

It took 12 hours to lose the water

Step-by-step explanation:

The total amount of water lost from Gerald’s bucket is inch

The amount of water he estimated to be lost in a single hour is inch

Dividing the total water lost by water lost per hour, we can get the the total number of hours it took to lose the water.

Therefore, it took 12 hours to lose the water.

3 0

3 years ago

92 = -4(2r - 5) r = ? Help!

Roman55 [17]

Hello there!

$92 = -4(2r - 5)\\$

Explanation:

↓↓↓↓↓↓↓↓↓↓↓↓

First you had to switch sides.

$-4(2r-5)=92$

Then you divide by -4 from both sides of the equation.

$\frac{-4(2r-5)}{-4}=\frac{92}{-4}$

Simplify

$2r-5=-23$

Next you had to add by 5 from both sides of the equation.

$2r-5+5=-23+5$

Simplify

$2r=-18$

You can also divide by 2 from both sides of the equation.

$\frac{2r}{2}=\frac{-18}{2}$

Simplify it should be the correct answer.

$r=-9$

Answer⇒⇒⇒⇒⇒r=-9

Hope this helps!

Thank you for posting your question at here on Brainly.

Have a great day!

-Charlie

5 0

4 years ago

Read 2 more answers

Which of the following is the complete list of roots for the polynomial function f(x)= (x^2-2x-15)(x^2+8x+17)

alexgriva [62]

Answer:

The complete set of roots is 5, -3, –4 + i, –4 – i

Step-by-step explanation:

The given polynomial is

$f(x)=(x^2-2x-15)(x^2+8x+17)$

We equate to zero to get:

$(x^2-2x-15)(x^2+8x+17)=0$

$(x^2-5x+3x-15)(x^2+8x+17)=0$

$(x(x-5)+3(x-5)(x^2+8x+17)=0$

$(x+3)(x-5)(x^2+8x+17)=0$

This implies that:

x+3=0,or x-5=0 or $(x^2+8x+17)=0$

x=-3,or x=5

For $(x^2+8x+17)=0$ , we use the quadratic formula to get;

$x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}$

where a=1,b=8,c=17

$x=\frac{-8\pm\sqrt{8^2-4(1)(17)} }{2(1)}$

$x=\frac{-8\pm\sqrt{-4} }{2}$

$x=-4-i$ or $x=-4+i$

The complete solution is 5, -3, –4 + i, –4 – i

5 0

3 years ago

Read 2 more answers