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nevsk [136]
4 years ago
14

1. The trucks hauling asphalt have a maximum capacity of 5 US tons (10,000 lbs) 2. The standard road lane is 12 feet wide. 3. As

phalt weighs 150 lbs per cubic foot 4. Asphalt costs $200 per ton 5. Power and water utilities are run in a conduit pipe under the road as part of all road projects 6. Conduit pipe is available only in 24 ft. lengths - each length costs $500 7. There is one intersection for every mile of road a. a 1 mile road has 1 intersection b. a 2 mile road has 2 intersections c. a 2.99 mile road has 2 intersections 8. Stoplights cost $25,000 per light 9. Each intersection has two stoplights, plus one additional stoplight for each lane a. a 1 lane road has three stop lights at each intersection b. a 2 lane road has four stop lights at each intersection c. a 3 lane road has five stop lights at each intersection 10. Work days are 8-hour days 11. All workers are paid $25 per hour12. Crew members can complete an amount of work in a specified time according to the equation below: crewMember = 50 . miles . lanes/days Test Data Test #1 Given Inputs Length of road project (miles) : 2.75 Number of lanes 3Depth of asphalt (inches) 12 Days to complete project 30Expected Output - Amount of materials needed === Truckloads of Asphalt : 7841 Stoplights : le Conduit pipes : 605 Crew members needed : 14 = Cost of Materials ============ Cost of Asphalt : $7841000.ee Cost of Stoplights : $250000.00 Cost of Conduit pipes : $302500.ee Cost of Labor : $84882.ee - Total Cost of Project - Total cost of project : $8477500.ee
Computers and Technology
1 answer:
ivolga24 [154]4 years ago
5 0

Answer:

please write in a better way, and make it easy for us to read.

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Linda is viewing the campaign report in her Google Ads account after successfully implementing conversion tracking tags for her
anyanavicka [17]

Answer:

Option 1 and Option 3 are correct.

Explanation:

Linda is displaying that marketing update within the Google Advertising profile after effectively installing transformation monitoring tags to its site. She saw that slightly two of her advertising are created by the following View-through transformations.

Thus, somebody seeing up towards Thirty seconds of such advertisements as well as anyone clicking on a portion of such advertising as View-through transformations.

6 0
3 years ago
Polygon transform (25 points). Write a library of static methods that performs various geometric transforms on polygons. Mathema
kari74 [83]

Answer:

import java.lang.*;               //for using Math.cos() and Math.sin() and Math.toRadians() funcitons in rotate method

public class PolygonTransform

{

  public static double[] copy(double[] array)

  {

      double[] newArray = new double[array.length];

      for(int i=0;i<array.length;i++)

      {

          newArray[i] = array[i];

          return newArray;

      }

  }

  public static void scale(double[]x,double[]y,double alpha)

  {

      for(int i=0;i<x.length;i++)

      {

          x[i] *= alpha;

          y[i] *= alpha;

      }

  }

  public static void translate(double[]x,double[]y,double dx,double dy)

  {

      for(int i=0;i<x.length;i++)

      {

          x[i] += dx;

          y[i] += dy;

      }

  }

  public static void rotate(double[] x, double[]y,double theta)

  {

      double rad = Math.toRadians(theta);

      double temp;

      for(int i=0;i<x.length;i++)

      {

          temp = x[i];                           //For storing temporarily the previous value of x before changing so tha it can be used in changing y

          x[i] = x[i]*Math.cos(rad) - y[i]*Math.sin(rad);

          y[i] = y[i]*Math.cos(rad) + temp*Math.sin(rad);  

      }

  }

  public static void main(String args[])

  {

      //This is just implementing you testcase discripted.

      double[]x = new double[4];

      double[]y = new double[4];

      StdDraw.setScale(-5.0, +5.0);

      x = { 0, 1, 1, 0 };

      y = { 0, 0, 2, 1 };

      double alpha = 2.0;

      StdDraw.setPenColor(StdDraw.RED);

      StdDraw.polygon(x, y);

      scale(x, y, alpha);

      StdDraw.setPenColor(StdDraw.BLUE);

      StdDraw.polygon(x, y);

      // Translates polygon by (2, 1).

      StdDraw.setScale(-5.0, +5.0);

      x = { 0, 1, 1, 0 };

      y = { 0, 0, 2, 1 };

      double dx = 2.0, dy = 1.0;

      StdDraw.setPenColor(StdDraw.RED);

      StdDraw.polygon(x, y);

      translate(x, y, dx, dy);

      StdDraw.setPenColor(StdDraw.BLUE);

      StdDraw.polygon(x, y);

      // Rotates polygon 45 degrees.

      StdDraw.setScale(-5.0, +5.0);

      x = { 0, 1, 1, 0 };

      y = { 0, 0, 2, 1 };

      double theta = 45.0;

      StdDraw.setPenColor(StdDraw.RED);

      StdDraw.polygon(x, y);

      rotate(x, y, theta);

      StdDraw.setPenColor(StdDraw.BLUE);

      StdDraw.polygon(x, y);

  }

}

Explanation:

6 0
3 years ago
A nonlinear optimization problem is any optimization problem in which at least one term in the objective function or a constrain
MAXImum [283]

Answer:

Yes

Explanation:

A nonlinear optimization problem is indeed a optimization problem in which there are nonlinear elements involved either as the objective function or one or more constraints may be nonlinear also. Let me show you an example. Let optimize de following function:

f(x) = x_{1} +x_{2}

These are the constraints:

x_{1} \geq  0\\x_{2} \geq  0\\\\x_{1} ^{2} +  x^{2}_{2}  \geq  1

The last constraint consists on nonlinear elements, so this problem in fact a nonlinear optimization problem.

5 0
3 years ago
Suppose Alice uses the RSA system with a very large modulus n for which the factorization cannot be found in a reasonable amount
Yuliya22 [10]

Answer:

Encryption method security:-

  • Encryption method representing each alphabetic character as an integer between 0 and 25.
  • Now, apply RSA algorithm for each integer is not an efficient secure encryption method.

Explanation:

  • Let consider alphabetic characters set {A, B... Z} .
  • Each alphabetic character forms a set of message block values M={0,1,2...,25).
  • From encryption method the corresponding cipher text block value C = {0e mod n,1e mod n, 2e mod n,..., 25e mod n}.
  • Then, compute the cipher text with knowledge of Bob's public key;
  • If the public key is generated, then possibility to decrypt the cipher text to plain text.
  • The generated public key is easily calculated by everyone and security is lost.
  • Therefore, the encryption method is not secure.

Encryption method is not secure, Most efficient attack against this method:-

  • Now, compute the encryption message with the function Me mod n for all the possible values of M.
  • This is the most efficient attack against the scheme in encryption method.
  • Then, create a look-up table with cipher text as an index to the corresponding plain text as a value for appropriate location in the table.
4 0
3 years ago
Complex layouts are often created in Java GUIs by using multiple _____ components
mixas84 [53]

Answer: JPanel

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4 0
3 years ago
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