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maksim [4K]
4 years ago
6

Why do some kinds of ice on Earth change the sea level when they melt while others do not?

Physics
1 answer:
maxonik [38]4 years ago
6 0
Some ice has more salt then the other causing it to float up
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Which part of the roller coaster system determines the amount of kinetic energy in the system
eduard
The lowest point, where the amount of energy is the greatest
5 0
4 years ago
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Your fitness tracker tells you that you have delivered 124 kJ of work during your workout. The tracker also shows that you have
REY [17]

To solve this problem, we must basically count the total energy lost converting all the values given in the international system.

The energy loss is given by both 124KJ and 124food heats.

Since the energy conversion we know that 1 food calories is equal to 4,184J. So:

124 calories (\frac{4.184J}{1 calories}) = 518.816J = 0.518816kJ

Therefore the total energy lost will be

E_{lost} = 124 KJ + 0.518816 KJ

E_{lost} = 124.518KJ

Therefore the total energy lost to the surroindings in form of heat is 124.518kJ

3 0
3 years ago
What happens to the size of atoms as we go from left to right on the periodic table? T
Lady_Fox [76]

Answer:

Atomic size gradually decreases from left to right across a period of elements.

Explanation:

This is because, within a period or family of elements, all electrons are added to the same shell. However, at the same time, protons are being added to the nucleus, making it more positively charged.

8 0
3 years ago
: The maximum theoretical efficiency of a Carnot engine operating between reservoirs at the steam point and at room temperature
Hunter-Best [27]

Answer:

The value is   \eta  =  0.2145  or  21.45%

Explanation:

From the question we are told that

    The first reservoir is at steam point  T_s =  100^o C =  100 + 273 = 373 \ K  

    The  second reservoir is at room temperature T_r  =  20^o C = 293 \ K

Generally the  maximum theoretical efficiency of a Carnot engine  is mathematically evaluated as

     \eta  =  1- \frac{T_r}{T_s}

=>    1 - \frac{ 293}{373}

=>    \eta  =  0.2145

5 0
3 years ago
A .1 kg mass is attached to a string 75 cm long and swings in a horizontal circle, revolving once every .8s. calculate the tensi
Valentin [98]

Answer:

4.62N

Explanation:

Since the motion covers 1 circle (or 2π rad) per 0.8 seconds, its angular velocity is

\omega=2\pi/0.8 = 7.85 rad/s

Radius of the circular motion is r = 75 cm or 0.75m. We can calculate the centripetal acceleration of this mass

a_c = \omega^2r = 7.85^2 * 0.75 = 46.2 m/s^2

From Newton's 2nd law, we calculate the centripetal force, which is also the tension of the string:

F_c = a_cm = 46.2 * 0.1 = 4.62 N

5 0
4 years ago
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