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4 years ago

Which part of the roller coaster system determines the amount of kinetic energy in the system

Physics

2 answers:

larisa [96]4 years ago

7 0

Answer:the roller coaster cars

Explanation:

eduard4 years ago

5 0

The lowest point, where the amount of energy is the greatest

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When Jacob bats a baseball with a net force of 4.719 N, it accelerates 33 m/s2. What is the mass of the baseball?

andreev551 [17]

Answer:

Mass=0.143 kg

Explanation:

From the Newton's second law of motion the force applied to an object is directly proportional to the acceleration produced and the acceleration is in the direction of the force.

F=ma where F is the force, m is the mass of the object and a i the acceleration.

m=F/a

=4.719N/33 m/s²

=0.143 kg

5 0

3 years ago

A ball is kicked at 30.0 m/s at an angle of 20.0°. Beneath the tilted columns calculate the vertical and horizontal components.

RSB [31]

The velocities at time t are

• Horizontal:

v = (30.0 m/s) cos(20.0º)

• Vertical:

v = (30.0 m/s) sin(20.0º) - g t

(where g = 9.80 m/s² is the magnitude of the acceleration due to gravity)

If you only want the initial velocities, they are

• Horizontal:

v = (30.0 m/s) cos(20.0º) ≈ 28.2 m/s

• Vertical:

v = (30.0 m/s) sin(20.0º) ≈ 10.3 m/s

(just set t = 0)

As far as starting equations go, you can derive everything from the definition for average acceleration:

a = ∆v / ∆t = (final v - initial v) / t

→ v = u + a t

(here, u stands in for "initial v" and v is simply velocity at time t )

There is no acceleration in the horizontal direction, while the ball is essentially in free-fall in the vertical direction.

6 0

3 years ago

A 650-kg elevator starts from rest. It moves upward for 3.00 s with constant acceleration until it reaches its cruis- ing speed

Nataly_w [17]

Answer: $P=5573.43\ W$

Explanation:

Given

Mass of the elevator is $M=650\ kg\\\$

Time period of ascension $t=3\ s$

cruising speed $v=1.75\ m/s$

Distance moved by elevator during this time

Suppose Elevator starts from rest

$\Rightarrow v=u+at\\\Rightarrow 1.75=0+a(3)\\\Rightarrow a=0.583\ s$

Distance moved

$\Rightarrow h=ut+0.5at^2\\\Rightarrow h=0+0.5\times 0.5833\times (3)^2\\\Rightarrow h=2.62\ m$

Gain in Potential Energy is

$\Rightarrow E=mgh\\\Rightarrow E=650\times 9.8\times 2.62\\\Rightarrow E=16,720.3\ N$

Average power during this period is

$\Rightarrow P=\dfrac{E}{t}\\\\\Rightarrow P=\dfrac{16,720.3}{3}\\\\\Rightarrow P=5573.43\ W$

7 0

3 years ago

Read 2 more answers

Differentiate between basic quantities and physical quantities

Anuta_ua [19.1K]

Answer:

Base quantities are the minimum numbers of the physical quantities. Base quantities are defined as the physical quantities which can not be defined in terms of other physical quanities. There are seven base quantities. Physical Quantitie Units Derived Quantities are defined as those physical quantities which are derived from the base quantities.

Explanation:

A physical quantity is a property of a material or system that can be quantified by measurement. A physical quantity can be expressed as the combination of a numerical value and a unit. For example, the physical quantity mass can be quantified as n kg, where n is the numerical value and kg is the unit. A physical quantity possesses at least two characteristics in common, one is numerical magnitude and other is the unit in which it is measured.

Distinguish between a basic physical quantity and a derived physical quantity giving an example of each. Answers. Basic physical quantities are quantities which can be obtained without derivation. e.g Temperature. While derived physical quantities are quantities which can only be obtained from other physical quantities.

5 0

3 years ago

Calculate the height of a cliff if it takes 2.35s for a rock to hit the ground when it is thrown straight up from the cliff with

ad-work [718]

Answer:

y₀ = 10.625 m

Explanation:

For this exercise we will use the kinematic relations, where the upward direction is positive.

y = y₀ + v₀ t - ½ g t²

in the exercise they indicate the initial velocity v₀ = 8 m / s.

when the rock reaches the ground its height is zero

0 = y₀ + v₀ t - ½ g t²

y₀i = -v₀ t + ½ g t²

let's calculate

y₀ = - 8 2.5 + ½ 9.8 2.5²

y₀ = 10.625 m

7 0

3 years ago