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slava [35]
3 years ago
12

Which situation describes a system with decreasing gravitational potential energy?

Physics
1 answer:
lord [1]3 years ago
6 0

Answer: a boy jumping down

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A mass is set oscillating horizontally, with an amplitude of 11.3 cm and a period of 0.702 sec. What is the velocity of the part
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Answer:

Explanation:

18.1

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What does nuclear fission have to do with the birth of stars?
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Fission is the process by which large nuclei (like Uranium) split apart releasing energy. Fusion is the joining of nuclei to make larger nuclei, with the release of energy. A ball of contracting interstellar gas becomes a star like the Sun when fusion reactions start in its center. Then, we say "a star is born."

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If a car collides with a moving bus, what type of relationship exists between the force of the car and the force of the bus?.
Troyanec [42]

The correct answer is forces are equal but opposite in direction between car and bus.

What do we mean by Collision?

When two objects collide, forces of equal magnitude and opposite direction are applied to each object. Such pressures frequently result in one thing gaining momentum and gaining speed while the other object slows down (lose momentum).

The force applied to an object to cause an impact—a change in momentum—on it is referred to as the impact force, or momentum. Technically speaking, the Car and the bus would have exerted and felt the same amount of impact force in the event of a collision. Because every action has a corresponding and opposing response, according to Newton's third law.

To learn more about Collision from the given link

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1 year ago
A bicycle going 10 m/s on a flat road demonstrates __________ energy.
vampirchik [111]
Then it demonstrate KINETIC ENERGY.
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3 years ago
A proton in a uniform electric field moves along a straight line with constant acceleration. Starting from rest it attains a vel
Sav [38]

a) The acceleration of the proton is 5.0\cdot 10^{13} m/s^2

b) The time required to reach the given velocity is 2\cdot 10^{-8}s

Explanation:

a)

This is a motion at constant acceleration, so we can use the following suvat equation:

v^2-u^2=2as

where

v is the final velocity

u is the initial velocity

a is the acceleration

s is the distance covered

For the proton in this problem, we have:

v=1,000,000 m/s is the final velocity

u=0 is the initial velocity (it starts from rest)

s = 0.01 m is the distance covered

Solving for a, we find the acceleration:

a=\frac{v^2-u^2}{2s}=\frac{(1,000,000)^2-0}{2(0.01)}=5.0\cdot 10^{13} m/s^2

b)

For this part, we can use the following suvat equation instead:

v=u+at

where:

v is the final velocity

u is the initial velocity

a is the acceleration

t is the time taken for the velocity to change from u to v

We have here the following data:

v=1,000,000 m/s is the final velocity

u=0 is the initial velocity (it starts from rest)

a=5.0\cdot 10^{13} m/s^2

Solving for t, we find

t=\frac{v-u}{a}=\frac{1,000,000}{5.0\cdot 10^{13}}=2\cdot 10^{-8}s

Learn more about accelerated motion here:

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5 0
3 years ago
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