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sashaice [31]
3 years ago
11

Which one of the following situations is NOT Possible? A body has zero velocity and non-zero acceleration. A body travels with a

northward velocity and a southward acceleration. A body travels with a northward velocity and a northward acceleration. A body travels with a constant velocity and a constant non-zero acceleration. A body travels with a constant acceleration and a time-varying velocity.
Physics
1 answer:
SSSSS [86.1K]3 years ago
4 0

Answer:

Explanation:

A body has zero velocity and non- zero acceleration. It is possible as at the time when a body thrown upwards is at the top of the height. In that case velocity is zero but acceleration is equal to g.

A body travels with northward velocity but southward acceleration . it is also possible as in case when a body is going with northward velocity  but when break is applied acceleration becomes  southward.

A body travels with northward velocity and northward  acceleration . it is also possible as in case when a body is going with northward velocity  and  when accelerator  is applied . Acceleration becomes northward.

A body travels with constant velocity and a constant non zero acceleration . It is not possible . When there is acceleration , there must be a a change in velocity either in terms of magnitude or direction or both.

A body travels with a constant acceleration and a time varying velocity. It is possible. Time varying velocity represents acceleration.

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An adult (mass 98.36kg) is standing on top of a 4.45m cliff right next to a river. He grabs a vine of length 30.1m, which the po
Tom [10]

Answer:

1. 2.98m/s

2. 0.28m

Explanation:

The energy equation would work great in this scenario:

E=K+U. Since all of our energy comes from gravitational potential energy, and we are interested in finding the kinetic energy, all our mechanical energy must be in kinetic form, therefore:

mgy=1/2mv^2+0\\98.36*4.45=1/2*98.36*v^2\\437.7=49.18v^2\\8.9=v^2\\2.98=v

We can use energy to find max height.

For energy, set the equation E=K+U as 437.7=(mass adult+mass senior)gh:

437.7=155.89gh\\\\2.8=gh\\0.28=h

8 0
2 years ago
A cantilever beam with a width b=100 mm and depth h=150 mm has a length L=2 m and is subjected to a point load P =500 N at B. Ca
DerKrebs [107]

Answer:

Explanation:

Given that:

width b=100mm

depth h=150 mm

length L=2 m =200mm

point load P =500 N

Calculate moment of inertia

I=\frac{bh^3}{12} \\\\=\frac{100 \times 150^3}{12} \\\\=28125000\ m m^4

Point C is subjected to bending moment

Calculate the bending moment of point C

M = P x 1.5

= 500 x 1.5

= 750 N.m

M = 750 × 10³ N.mm

Calculate bending stress at point C

\sigma=\frac{M.y}{I} \\\\=\frac{(750\times10^3)(25)}{28125000} \\\\=0.0667 \ MPa\\\\ \sigma =666.67\ kPa

Calculate the first moment of area below point C

Q=A \bar y\\\\=(50 \times 100)(25 +\frac{50}{2} )\\\\Q=250000\ mm

Now calculate shear stress at point C

=\frac{FQ}{It}

=\frac{500*250000}{28125000*100} \\\\=0.0444\ MPa\\\\=44.4\ KPa

Calculate the principal stress at point C

\sigma_{1,2}=\frac{\sigma_x+\sigma_y}{2} \pm\sqrt{(\frac{\sigma_x-\sigma_y}{2} ) + (\tau)^2} \\\\=\frac{666.67+0}{2} \pm\sqrt{(\frac{666.67-0}{2} )^2 \pm(44.44)^2} \ [ \sigma_y=0]\\\\=333.33\pm336.28\\\\ \sigma_1=333.33+336.28\\=669.61KPa\\\\\sigma_2=333.33-336.28\\=-2.95KPa

Calculate the maximum shear stress at piont C

\tau=\frac{\sigma_1-\sigma_2}{2}\\\\=\frac{669.61-(-2.95)}{2}  \\\\=336.28KPa

6 0
3 years ago
Which imaging technique uses radiation that is emitted from the material being imaged
garri49 [273]

Answer:

Positron emission tomography. Positron emission tomography (PET) is an imaging technique that uses radioactive substances to visualize and measure metabolic processes in the body.

4 0
4 years ago
Read 2 more answers
Who studies this branch of physics? What types of careers are there in this branch of physics? What particular subjects should s
kolezko [41]

The answers to all three questions depend on WHICH branch

of Physics you're talking about . . . a piece of information you've

neglected to specify.

8 0
4 years ago
PLEASE ANSWER! A sound Wave with a frequency of 100.0 Hz travels in water with a speed of 1,500 m/s and then travels in air with
Sedaia [141]

Answer:

ok

Explanation:

12345-7543

8 0
3 years ago
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