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2 years ago

Please help me out as soon as you can. Really need help.

Physics

1 answer:

olga nikolaevna [1]2 years ago

4 0

The answer would be 6 because 2.0x3= 6

(newton’s 2nd law)

mark me brainliest

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Black holes must have a mass three or more times the mass of _____.

tia_tia [17]

The answer is <span>d. the sun</span>

7 0

3 years ago

Read 2 more answers

A 3.00N rock is thrown vertically into the air from the ground. At h=15.0m, v=25m/s upward. Use the work-energy theorem to find

butalik [34]

Answer:

so initial speed of the rock is 30.32 m/s

correct answer is b. 30.3 m/s

Explanation:

given data

h = 15.0m

v = 25m/s

weight of the rock m = 3.00N

solution

we use here work-energy theorem that is express as here

work = change in the kinetic energy ..............................1

so it can be written as

work = force × distance ...................2

and

KE is express as

K.E = 0.5 × m × v²

and it can be written as

F × d = 0.5 × m × (vf)² - (vi)² ......................3

here

m is mass and vi and vf is initial and final velocity

F = mg = m (-9.8) , d = 15 m and v{f} = 25 m/s

so put value in equation 3 we get

m (-9.8) × 15 = 0.5 × m × (25)² - (vi)²

solve it we get

(vi)² = 919

vi = 30.32 m/s

so initial speed of the rock is 30.32 m/s

5 0

3 years ago

The roller coaster car has a mass of 700 kg, including its passenger. If it is released from rest at the top of the hill A, dete

sweet [91]

Answer:

$h = 18.75 m$

Now when it will reach at point B then its normal force is just equal to ZERO

$N_B = 0$

$F_n = 1.72 \times 10^4$

Explanation:

Since we need to cross both the loops so least speed at the bottom must be

$v = \sqrt{5 R g}$

also by energy conservation this is gained by initial potential energy

$mgh = \frac{1}{2}mv^2$

$v = \sqrt{2gh}$

so we will have

$\sqrt{2gh} = \sqrt{5Rg}$

now we have

$h = \frac{5R}{2}$

here we have

R = 7.5 m

so we have

$h = \frac{5(7.5)}{2}$

$h = 18.75 m$

Now when it will reach at point B then its normal force is just equal to ZERO

$N_B = 0$

now when it reach point C then the speed will be

$mgh - mg(2R_c) = \frac{1}{2]mv_c^2$

$v_c^2 = 2g(h - 2R_c)$

$v_c = 13.1 m/s$

now normal force at point C is given as

$F_n = \frac{mv_c^2}{R_c} - mg$

$F_n = \frac{700\times 13.1^2}{5} - (700 \times 9.8)$

$F_n = 1.72 \times 10^4$

7 0

3 years ago

!!!!!!PLEASE HELP ASAP !!!!!!!!!!!!

OLga [1]

Answer: d constint speed

Explanation: im 15 and no the answer

5 0

2 years ago

A health care provider suspects a client has developed posttraumatic stress disorder (PTSD). Select the necessary criterion to v

julia-pushkina [17]

Answer:

The necessary criterion to validate the PTSD (posttraumatic stress disorder) is criterion A, (one required): the person was exposed to: death, threatened death, actual or threatened serious injury, or actual or threatened sexual violence,one symptom (or more): inability to remember an important aspect of the event, from criterion B, one symptom (or more): wars survivors, persistent and exaggerated negative beliefs about oneself, others, or the world, and persistent negative emotional state.to criterion C: old age abused; persistent distorted cognitions about the cause or consequences of the event.

Explanation:

DSM-5 PTSD diagnosis measures, assesses, or evaluates dissociative subtypes, which causes disconnection from the surrounding world or from oneself.

The DSM-5 manual, for the PTSD diagnosis, includes the DSM-IV/ICD-9 309.81 to the ICD-10 F43.10.

An experienced mental health provider, such as a psychiatrist or psychologist, is generally in charge of the diagnosis.

To be diagnosed with PTSD, an adult must have at least one avoidance symptom re-experiencing symptom for at least 1 month.

8 0

2 years ago