Answer:
∆L=aL∆T
Explanation:
that's the answer for your Question
Ultraviolet radiation from the sun is controlled by the ozone but if it infiltrates into the atmosphere it becomes a hazard. The uv reaches our eyes and darkens the retina and blurs vision. The fovea becomes insensitive and the cells dormant. This causes gradual blindness.
Answer:
Pressure = 20 MPa
Explanation:
Given:
Force acting on the shoe is, ![F=100\ N](https://tex.z-dn.net/?f=F%3D100%5C%20N)
Area of shoe on which the force acts is, ![A= 0.05\ cm^2](https://tex.z-dn.net/?f=A%3D%200.05%5C%20cm%5E2)
Now, first we convert the area into its standard unit of m².
We have the conversion factor as:
1 cm² = ![10^{-4}\ m^2](https://tex.z-dn.net/?f=10%5E%7B-4%7D%5C%20m%5E2)
Therefore, the area of shoe in square meters is given as:
![A=0.05\times 10^{-4}\ m^2\\A=5\times 10^{-6}\ m^2](https://tex.z-dn.net/?f=A%3D0.05%5Ctimes%2010%5E%7B-4%7D%5C%20m%5E2%5C%5CA%3D5%5Ctimes%2010%5E%7B-6%7D%5C%20m%5E2)
Now, pressure on the shoe is given as:
![P=\frac{Force}{Area}\\P=\frac{F}{A}](https://tex.z-dn.net/?f=P%3D%5Cfrac%7BForce%7D%7BArea%7D%5C%5CP%3D%5Cfrac%7BF%7D%7BA%7D)
Plug in 100 N for 'F',
for 'A' and solve for 'P'. This gives,
![P=\frac{100\ N}{5\times 10^{-6}\ m^2}\\P=20\times 10^{6}\ N/m^2](https://tex.z-dn.net/?f=P%3D%5Cfrac%7B100%5C%20N%7D%7B5%5Ctimes%2010%5E%7B-6%7D%5C%20m%5E2%7D%5C%5CP%3D20%5Ctimes%2010%5E%7B6%7D%5C%20N%2Fm%5E2)
Now, we know that,
![10^{6}\ N/m^2=1\ MPa\\\therefore 20\times 10^{6}\ N/m^2=20\times 1\ MPa=20\ MPa](https://tex.z-dn.net/?f=10%5E%7B6%7D%5C%20N%2Fm%5E2%3D1%5C%20MPa%5C%5C%5Ctherefore%2020%5Ctimes%2010%5E%7B6%7D%5C%20N%2Fm%5E2%3D20%5Ctimes%201%5C%20MPa%3D20%5C%20MPa)
Therefore, the pressure acting on the shoe is 20 MPa.
Answer:
w_f = m*V*cos(Q_n) / L*(m+M)
Explanation:
Given:
- mass of the putty ball m
- mass of the rod M
- Velocity of the ball V
- Length of the rod L
- Angle the ball makes before colliding with rod Q_n
Find:
What is the angular speed ωf of the system immediately after the collision,
Solution:
- We can either use conservation of angular momentum or conservation of Energy. We will use Conservation of angular momentum of a system:
L_before = L_after
- Initially the rod is at rest, and ball is moving with the velocity V at angle Q from normal to the rod. We know that the component normal to the rod causes angular momentum. Hence,
L_before = L_ball = m*L*V*cos(Q_n)
- After colliding the ball sicks to the rod and both move together with angular speed w_f
L_after = (m+M)*L*v_f
Where, v_f = L*w_f
L_after = (m+M)*L^2 * w_f
- Now equate the two expression as per conservation of angular momentum:
m*L*V*cos(Q_n) = (m+M)*L^2 * w_f
w_f = m*V*cos(Q_n) / L*(m+M)
Answer:
Some more uses of ultrasonic are cleaning of difficult component, Echolocation etc. 1-Leakage detection in Pipelines--Infrasonic waves is used to detect the leakage in Pipelines etc. It shows the accurate point from where the tiny leakage occurs. It detect the signal through algorithm and separate it quickly.
Explanation: