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WARRIOR [948]
2 years ago
7

An adult (mass 98.36kg) is standing on top of a 4.45m cliff right next to a river. He grabs a vine of length 30.1m, which the po

int of support is directly above a senior (mass 57.53kg). The adult grabs the senior at the bottom of his swing and has just enough speed to make it to the cliff on the other side. What would be the adult’s speed right before he catches the senior? What is the maximum height of the cliff that both of them can reach?
Physics
1 answer:
Tom [10]2 years ago
8 0

Answer:

1. 2.98m/s

2. 0.28m

Explanation:

The energy equation would work great in this scenario:

E=K+U. Since all of our energy comes from gravitational potential energy, and we are interested in finding the kinetic energy, all our mechanical energy must be in kinetic form, therefore:

mgy=1/2mv^2+0\\98.36*4.45=1/2*98.36*v^2\\437.7=49.18v^2\\8.9=v^2\\2.98=v

We can use energy to find max height.

For energy, set the equation E=K+U as 437.7=(mass adult+mass senior)gh:

437.7=155.89gh\\\\2.8=gh\\0.28=h

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In order to move a bag of dog food across a 10 meter room you apply20 Newton’s of force how much work was done?
lilavasa [31]
The work done is calculated by multiplying the Force by the distance. So, 10x20 = 200 joules.
I hope this is the answer you are looking for, if not good luck on finding your answer ;D
8 0
3 years ago
A rock is attached to the left end of a uniform meter stick that has the same mass as the rock. How far from the left end of the
kotykmax [81]

Answer:

M₂ = M  then L₂ = L

M₂> M  then L₂ = \frac{M}{M_{2}} L

Explanation:

This is a static equilibrium exercise, to solve it we must fix a reference system at the turning point, generally in the center of the rod. By convention counterclockwise turns are considered positive

          ∑ τ = 0

           

The mass of the rock is M and placed at a distance, L the mass of the rod M₁, is considered to be placed in its center of mass, which by uniform e is in its geometric center (x = 0) and the triangular mass M₂, with a distance L₂

The triangular shape of the second object determines that its mass can be considered concentrated in its geometric center (median) that tapers with a vertical line if the triangle is equilateral, the most used shape in measurements.

         M L + M₁ 0 - m₂ L₂ = 0

         M L - m₂ L₂ = 0

         L₂ = \frac{M}{M_{2}} L

From this answer we have several possibilities

* if the two masses are equal then L₂ = L

* If the masses are different, with M₂> M then L₂ = \frac{M}{M_{2}} L

6 0
3 years ago
Please solve it ,,,,,,,,,,................................
fredd [130]

Answer:

the distance covered by the body in 5th second =u+a(n- 1/2)=7+4(5- 1/2)

=7+4×9/2

=7+18

=25m

6 0
3 years ago
If a ball leaves the ground with a vertical velocity of 5.46 m/s, how long does it take
kifflom [539]

Answer:

0.557 s

Explanation:

Given:

v₀ = 5.46 m/s

v = 0 m/s

a = -9.8 m/s²

Find: t

v = at + v₀

0 m/s = (-9.8 m/s²) t + 5.46 m/s

t = 0.557 s

8 0
3 years ago
4. The blades on a fan have a frequency of 15 Hz.
vichka [17]

Answer:

a) 4500 cycles b) 0.0667s c) 6.67s

Explanation:

a) 15 Hz= 15 cycles/ s

   5 mins= 300s

   15 cycles/s * 300s= 4500 cycles

b) Period= 1/ frequency

   Period= 1/ 15 cycles/s

   Period= 0.0667s

c) Period * number of revolutions= time

  0.0667 * 100= 6.67s

6 0
3 years ago
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