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worty [1.4K]
3 years ago
6

Who studies this branch of physics? What types of careers are there in this branch of physics? What particular subjects should s

omeone study if they want a job in this branch of physics?
Physics
1 answer:
kolezko [41]3 years ago
8 0

The answers to all three questions depend on WHICH branch

of Physics you're talking about . . . a piece of information you've

neglected to specify.

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Describe the relationship between the Law of Conservation of Matter and balancing equations.
Yuliya22 [10]

Answer:

The mass of the products and reactants are the same on both sides of the equation.

The number of atoms of products and reactants are equal and hence it proves the law of conservation of mass.

.

3 0
2 years ago
Read 2 more answers
An electron is accelerated from rest through a potential difference. After acceleration the electron has a de Broglie wavelength
Vladimir [108]

Answer:

3x10⁴v

Explanation:

Using

Wavelength= h/ √(2m.Ke)

880nm = 6.6E-34/√ 2.9.1E-31 x me

Ke= 6.6E-34/880nm x 18.2E -31.

5.6E-27/18.2E-31

= 3 x 10⁴ Volts

4 0
3 years ago
A girl of mass 55 kg throws a ball of mass 0.80 kg against a wall. The ball strikes the wall horizontally with a speed of 25 m/s
lisabon 2012 [21]

Answer:

Magnitude of the average force exerted on the wall by the ball is 800N

Explanation:

Given

Contact Time = t = 0.05 seconds

Mass (of ball) = 0.80kg

Initial Velocity = u = 25m/s

Final Velocity = 25m/s

Magnitude of the average force exerted on the wall by the ball is given by;

F = ma

Where m = 0.8kg

a = Average Acceleration

a = (u + v)/t

a = (25 + 25)/0.05

a = 50/0.05

a = 1000m/s²

Average Force = Mass * Average Acceleration

Average Force = 0.8kg * 1000m/s²

Average Force = 800kgm/s²

Average Force = 800N

Hence, the magnitude of the average force exerted on the wall by the ball is 800N

3 0
3 years ago
An open pipe of length 0.39 m vibrates in the third harmonic with a frequency of 1400 Hz what is the distance from the center of
Svetach [21]

Length of the pipe = 0.39 m

Number of harmonics = 3

Now there are 3 loops so here we can say

3\times \frac{\lambda}{2} = 0.39

\lambda = 0.26 m

now here at the center of the pipe it will form Node

we need to find the distance of nearest antinode

So distance between node and its nearest antinode will be

d = \frac{\lambda}{4}

d = \frac{0.26}{4} = 0.065 m = 6.5 cm

So the distance will be 6.5 cm

3 0
3 years ago
An undiscovered planet, many lightyears from Earth, has one moon in a periodic orbit. This moon takes 23.0 days on average to co
Gelneren [198K]

Answer:

See it in the pic

Explanation:

See it in the pic

7 0
3 years ago
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