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BabaBlast [244]
3 years ago
7

George cut a cake into 8 equal pieces. what is the unit fraction for the cake

Mathematics
1 answer:
trasher [3.6K]3 years ago
6 0

Answer: 1/8

Step-by-step explanation:

Unit Fractions: A unit fraction is a rational number written as a fraction where the numerator is one and the denominator is a positive integer. A unit fraction is therefore the reciprocal of a positive integer, 1/n.

Example of Unit Fractions: 1/1, 1/2, 1/3, 1/4 ,1/5, etc.

Hope this helps! Please mark as brainliest!

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2(3x+ 4)

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What are benchmarks when using rounding?
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Benchmark can be defined as the standard or reference point against which something can be measured, compared, or assessed.

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Expand the following expression: 4 (2k + j)
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Answer:

4(2k + j) = 8k + 4j

Step-by-step explanation:

4(2k + j)

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Goofy's fast food center wishes to estimate the proportion of people in its city that will purchase its products. Suppose the tr
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Answer:

The probability that the sample proportion will differ from the population proportion by greater than 0.03 is 0.0143.

Step-by-step explanation:

According to the Central limit theorem, if from an unknown population large samples of sizes <em>n</em>  ≥ 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.

The mean of this sampling distribution of sample proportion is:

 \mu_{\hat p}=p

The standard deviation of this sampling distribution of sample proportion is:

\sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}

The sample selected consists of <em>n</em> = 254 individuals. The sample is quite large, i.e. <em>n</em> = 254 > 30. So the central limit theorem can be applied to approximate the distribution of sample proportion of  people in the city that will purchase the products of Goofy's fast food.

The mean is:

\mu_{\hat p}=p=0.05

And the standard deviation is:

\sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}=\sqrt{\frac{0.05(1-0.05)}{254}}=0.0137

Now, we need to compute the probability that the sample proportion will differ from the population proportion by greater than 0.03.

That is:

\hat p-p>0.03\\\hat p -0.05>0.03\\\hat p>0.08

Compute the value of P(\hat p>0.08) as follows:

P(\hat p>0.08)=P(\frac{\hat p-\mu_{\hat p}}{\sigma_{\hat p}}>\frac{0.08-0.05}{0.0137})

                   =P(Z>2.19)\\=1-P(Z

*Use a <em>z</em>-tale for the probability.

Thus, the probability that the sample proportion will differ from the population proportion by greater than 0.03 is 0.0143.

8 0
3 years ago
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