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Ivahew [28]
3 years ago
11

8. Parallel to the line y = 2x + 5 and contains the

Mathematics
1 answer:
Shalnov [3]3 years ago
7 0

Answer:

y=2x-3

Step-by-step explanation:

So we want to find an equation in slope-intercept form that is parallel to:

y=2x+5

And contains the point (4,5).

So to create the equation, we will need to slope and the y-intercept.

First, recall that parallel lines have the same slope. Since we want our equation to be parallel to y=2x+5, this means that the slope of the new equation must be 2.

Now, we can use the point-slope form to solve for the y-intercept. The point slope form is:

y-y_1=m(x-x_1)

Let (4,5) be x₁ and y₁. m is 2 since it's parallel to y=2x+5. Thus:

y-5=2(x-4)\\

Distribute:

y-5=2x-8

Add 5 to both sides:

y=2x-3

And that's our equation :)

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The function of F is defined by f(x) = x + 2, the value of f(n - 4) is given as f(n - 4) = n - 4 + 2 = n - 2

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Given the equation:

f(x) = x + 2

The value of f(n - 4) is given as:

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If f(1) = 10 and f(n) = f(n = 1) – 4 then find the value of f(5).
svetoff [14.1K]

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f(1)=10 and f(n)=f(n-1)-4.

To find:

The value of f(5).

Solution:

We have,

f(n)=f(n-1)-4

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f(2)=f(2-1)-4

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For n=3,

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f(3)=2

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Answer:

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Step-by-step explanation:

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