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stepladder [879]
3 years ago
7

A certain four​-cylinder combination lock has 50 numbers on it. to open​ it, you turn to a number on the first​ cylinder, then t

o a second number on the second​ cylinder, and then to a third number on the third cylinder and so on until a four​-number lock combination has been affected. repetitions are​ allowed, and any of the 50 numbers can be used at each step to form the combination.​ (a) how many different lock combinations are​ there
Mathematics
2 answers:
Kaylis [27]3 years ago
8 0
There are 230,300 combinations.

This is given by

_nC_r = _{50}C_4=\frac{50!}{46!4!} = 230,300
kumpel [21]3 years ago
7 0

A certain four​-cylinder combination lock has 50 numbers on it.

It is a four cylinder combination lock

Each cylinder has 50 numbers

So we have to choose 4 numbers for 4 cylinders

_____ , ______ , ______, _____

you turn to a number on the first​ cylinder

We have 50 numbers so we have 50 combinations

__50___ , ______ , ______, _____

Repetitions are allowed so we do the same for remaining three

50 , 50 , 50 , 50

50 * 50 * 50* 50 = 6250000

There are 6250000 different lock combinations .

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sammy [17]

Answer:

C

Step-by-step explanation:

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3 years ago
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Find the value power of 3^4
Anastaziya [24]
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Alexandria is practicing her long distance running. On day 0, she can run 2 miles without stopping. She wants to add 1/4 mile to
monitta

Answer:

slope = 1/4

Step-by-step explanation:

If a equation is in form of y = mx + c

them m is the slope of line.

____________________________________________

Let Y(d) be the distance ran by Alexandria on dth day

Y(0) = 2

she adds 1/4 miles each day then

Y(1) = 2 + 1/4

Y(2) = 2 + 1/4 +1/4 = 2 +1/4(2)

Y(3) = 2 + 1/4 +1/4 +1/4= 2 +1/4(3)

.

.

.

.

similarly

in d days she can run 2 miles + 1/4*d miles

thus, we have

Y(d) = 2 + 1/4(d)

it can be also solved

Thus we see that it is a linear relationship y = 2 + 1/4(d)

which is in the form of y = mx + c

comparing mx to 1/4 d

we have m = 1/4

thus,

slope of this linear relationship is 1/4

8 0
3 years ago
Given: cosθ= -4/5 , sin x = -12/13 , θ is in the third quadrant, and x is in the fourth quadrant; evaluate tan 1/2 θ
mrs_skeptik [129]

Answer:

Step-by-step explanation:

If you're looking for what the half angle of the tangent of theta is, I'm a bit confused as to why you think the angle in the 4th quadrant, x, is relevant.  But maybe you don't know it isn't and it's a "trick" to throw you off.  Hmm...

Anyways, the half angle identity for tangent is

tan(\frac{\theta}{2})=\frac{sin\theta}{1+cos\theta}

There are actually 3 identities for the tangent of a half angle, but this one works just as well as either of the others do, so I'm going with this one.  

If theta is in QIII, the value of -4 goes along the x axis and the hypotenuse is 5.  That makes the missing side, by Pythagorean's Theorem, -3.  Filling in our formula:

tan(\frac{\theta}{2})=\frac{-\frac{3}{5} }{1+(-\frac{4}{5}) } which simplifies a bit to

tan(\frac{\theta}{2})=\frac{-\frac{3}{5} }{\frac{5}{5} -\frac{4}{5} }  and a bit more to

tan(\frac{\theta}{2})=\frac{-\frac{3}{5} }{\frac{1}{5} }

Bring up the lower fraction and flip it to divide to get

tan(\frac{\theta}{2})=-\frac{3}{5}*\frac{5}{1} which of course simplifies to

-3.  Choice A.

6 0
4 years ago
How do you graph (0,3.5)
bazaltina [42]

Answer:

In a coordinate axis, the horizontal line is called the x-axis, and the vertical line is called the y-axis.

1) Then if you have a point (x, y), to graph this you go at the horizontal axis to find the value x,

2) Starting from the point you already found, now you need to move y units in the vertical axis.

Now we want to graph the point (0, 3.5).

First we need to locate the value 0 in the horizontal axis, this is the point where both axes intersect.

Now we move 3.5 units, because the number is positive, we move 3.5 units upwards.

The graph of the point is shown below.

3 0
3 years ago
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