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3 years ago

Why is it easier to work with plants than animals when it comes to hybrids? Explain.

Advanced Placement (AP)

1 answer:

babunello [35]3 years ago

6 0

Plants can be sexual or asexual so it’s easier when it comes to hybrids.

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What is the answer to this math problem with full work advanced geometry

Alisiya [41]

Answer:

Chord UV = 5

Explanation:

Recall that Theorem of congruent chords relating to their arcs states that the intercepted arcs of two chords are congruent if the two chords are of the same length.

The converse of this theorem states that if two intercepted arcs of two corresponding chords are congruent, then the two chords are congruent to each other.

Let's apply the converse of this theorem to the problem given.

We are given that the intercepted arcs of chord UV and chord UT are 34° each.

Therefore, chord UV must be congruent to chord UT.

Since chord UT = 5

Therefore, chord UV = 5

6 0

3 years ago

Hello, I need help with a calculus FRQ. My teacher has given a hint that this last part has to do with the intermediate value th

lesya [120]

Answer:

Yes, at a time t such that (√2)/2 ≤ t ≤ 2.

Explanation:

To answer the question

Therefore, where the domain of the function is the set of all real numbers x for which f(x) is a real number we have

For Chloe's velocity

$C(t) = t\times e^{4-t^2} \ for \ 0\leq t\leq 2$

Finding the boundaries of the function gives;

$0\times e^{4-0^2} = 0$ and $2\times e^{4-2^2} = 2$

At t = 1, we have $1\times e^{4-1^2} = e^{3} = 20.086$

We find the maximum point as follows;

$\frac{\mathrm{d} \left (t\times e^{4-t^2} \right )}{\mathrm{d} x}=0$

From which we have;

$\frac{\mathrm{} e^{4-t^2} - t\times e^{4-t^2} \times2\times t }{(e^{4-t^2} )^2}=0$

$e^{4-t^2} - t\times e^{4-t^2} \times2\times t }=0$

$e^{4-t^2}(1 - t\times2\times t })=0\\e^{4-t^2}(1 - 2\times t^2 })=0\\$

$e^{4-t^2}=0$ or $(1 - 2\times t^2 })=0$

∴ 1 = 2·t² and from which t = (√2)/2

Hence the function C(x) is decreasing from t = (√2)/2 to t = 2

For Brandon

For 0 ≤ t ≤ 1, 1 ≤ B(t) ≤8 and for 1 < t ≤ 2, 8 < B(t) ≤ 1.5

1 ≤ f(x) ≤ 1.5

Given that the function B(t) is differentiable, therefore, continuous, there exists a point at which the function C(t) and B(t) intersects given that;

For 0 ≤ t ≤ (√2)/2, 0 ≤ C(t) ≤ 23.416 for (√2)/2 < t ≤ 2, 23.416 > C(t) ≥ 2

and for 0 ≤ t ≤ 0 1 ≤ B(t) ≤ 8 and for 1 < t ≤ 2, 8 > B(t) ≥ 1.5

Therefore, the curves intersect at in between (√2)/2 ≤ t ≤ 2.

8 0

3 years ago

It is important for your goals to be as outlandish as possible.<br> O True<br> False

balu736 [363]

Answer:

That's true I just took the little quiz myself

7 0

3 years ago

A recent recession has reduce the number of visitors at a local theme park the park has to lay off many of its employees includi

Maslowich

According to bureau of Labor statistics, Lucretia's unemployment would be categorized as cyclical unemployment.

<h3>The types of unemployment.</h3>

According to bureau of Labor statistics, unemployment is divided into various types and these include the following;

Frictional unemployment (FU).

Structural unemployment (SU).

Actual unemployment (AU).

Cyclical unemployment (CU).

In this scenario, Lucretia's unemployment would be categorized as cyclical unemployment because it was as a result of an economic factor known as recession.

Read more on cyclical unemployment here: brainly.com/question/16287968

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8 0

2 years ago

Which line of a SITREP report should contain a brief summary of enemy activity?

diamong [38]

The line of the SITREP report that should contain a brief summary of the enemy activity is in line 2. It is because line 1 is composed of the size observed in the enemy, line 3 tells about the location of the enemy. The line 4 is about the unit of the enemy of which it belongs. Line 5 us about the time and lastly, line 6 is about the equipment of the enemy.

6 0

3 years ago