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4 years ago

14

A relay team ran a race. Each team member ran #1/4# of the distance. The whole race was #8/9# mile. How far did each team member

run?

1 answer:

Andre45 [30]4 years ago

5 0

Each member ran 2/9 miles

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Step-by-step explanation:

5x7=35

35-4=31

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A rectangular picture frame has a width of 9 cm and a length of x cm.

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Ms. Armstrong is a carpenter. She keeps her tools in a cube-shaped box in her truck. Ms. Armstrong's toolbox is 15 inches long o

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D<br> Evaluate<br> arcsin<br> (6)]<br> at x = 4.<br> dx

sineoko [7]

Answer:

$\frac{1}{2\sqrt{5} }$

Step-by-step explanation:

Let, $\text{sin}^{-1}(\frac{x}{6})$ = y

sin(y) = $\frac{x}{6}$

$\frac{d}{dx}\text{sin(y)}=\frac{d}{dx}(\frac{x}{6})$

$\frac{d}{dx}\text{sin(y)}=\frac{1}{6}$

$\frac{d}{dx}\text{sin(y)}=\text{cos}(y)\frac{dy}{dx}$ ---------(1)

$\frac{1}{6}=\text{cos}(y)\frac{dy}{dx}$

$\frac{dy}{dx}=\frac{1}{6\text{cos(y)}}$

cos(y) = $\sqrt{1-\text{sin}^{2}(y) }$

= $\sqrt{1-(\frac{x}{6})^2}$

= $\sqrt{1-(\frac{x^2}{36})}$

Therefore, from equation (1),

$\frac{dy}{dx}=\frac{1}{6\sqrt{1-\frac{x^2}{36}}}$

Or $\frac{d}{dx}[\text{sin}^{-1}(\frac{x}{6})]=\frac{1}{6\sqrt{1-\frac{x^2}{36}}}$

At x = 4,

$\frac{d}{dx}[\text{sin}^{-1}(\frac{4}{6})]=\frac{1}{6\sqrt{1-\frac{4^2}{36}}}$

$\frac{d}{dx}[\text{sin}^{-1}(\frac{2}{3})]=\frac{1}{6\sqrt{1-\frac{16}{36}}}$

$=\frac{1}{6\sqrt{\frac{36-16}{36}}}$

$=\frac{1}{6\sqrt{\frac{20}{36} }}$

$=\frac{1}{\sqrt{20}}$

$=\frac{1}{2\sqrt{5}}$

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3 years ago

Rick is buying a small sailboat for $3,000 with a down payment of $1,000. The bank approved a simple interest flat rate loan for

Anni [7]

Option C

Monthly loan payment is $ 93.33

<em><u>Solution:</u></em>

From given question,

Cost of sailboat = $ 3000

Down payment = $ 1000

<em><u>Hence net principal is given as:</u></em>

net principal = p = $ 3000 - $ 1000 = $ 2000

p = $ 2000

The bank approved a simple interest flat rate loan for 2 years at 6% APR

Hence number of years = 2 years

Rate of interest = 6 %

<em><u>Let us first calculate the simple interest</u></em>

The formula for simple interest is given as:

$\text{ simple interest } = \frac{ p \times n \times r}{100}$

Substituting the given values,

$\text{ simple interest } = \frac{ 2000 \times 2 \times 6}{100}\\\\\text{ simple interest } = 20 \times 2 \times 6 = 240$

Thus simple interest = $ 240

Total amount payable = principal + simple interest

Total amount payable = $ 2000 + $ 240

Total amount payable = $ 2240

<em><u>How much are the monthly loan payments?</u></em>

Here number of years = 2 years

To calculate the monthly payment divide the total amount payable by 24 (since 2 year = 24 months )

$\text{ Monthly loan payment } = \text{ Total amount payable } \div 24$

$\text{ Monthly loan payment } = \frac{2240}{24} = 93.33$

Thus monthly loan payment is $ 93.33 Option C is correct

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3 years ago