In the secant secant theorem,
AP × BP = CP × DP
AP × 6 = 7 × 12
AP = 7 × 2 = 14
Answer: 14
Answer: option d. C (0,3), D (0,5).
Justification:
1) The x - coordinates of the vertices A and B are shown in the diagrama, They are both - 4, so the new vertices C and D must be in a line parallel to y = - 4.
2) The y-coordinates of the vertices A and B are also shown in the diagrama. They are equal to 3 and 5 respectively.
3) We can see that the new points C and D must be over a parallel line to y = - 4 and that their distance to the points A and B has to be the same distance of the point R and S to U and T.
That distance is 4, so the line may be y = - 7 or y = 0.
4) If the line is y = 7 the points C and D would have coordinates (-7,3) and (-7,5), but this points are not among the options.
5) If the line is y = 0 the points C and D would have coordinates (0, 3) and (0,5), which is precisely the points of the option d. That is the answer.
Answer:
I am telling I am new to this
Answer:
Approximately 0.333
Step-by-step explanation:
If we graph this we see that the line goes over the y-axis at (0,0.333)
*I use desmos graphing calculator*
