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Lera25 [3.4K]
3 years ago
6

Find the 7th term of the geometric sequence -5, 15, 45, 135, 405,...

Mathematics
1 answer:
katovenus [111]3 years ago
7 0

Answer:

1,215

Step-by-step explanation:

Because if you think of it it multiplies by 3x so 3x5=? 15! 15x3=? 45! 45x3=? 405! 405x=3? 1,215! 1,215x3=? 3,645! anyways, I can go on and on I hope this answer was right!

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A telemarketer earns $150 a week plus $2 for each call that results in sale. Last week she earned a total of $204. How many of h
cluponka [151]

Answer:

27 calls

Step-by-step explanation:

Let T(x) represent total sales.

Then T(x) = $150 + ($2/call)x, where x is the number of calls made.

If T(x)        = $204, we can solve for x, the number of calls made:

$204 = $150 + ($2/call)x, or

 $ 54

----------- = 27 calls

$2/call

8 0
3 years ago
Problem 1:
wariber [46]

Answer:

x=1/6

Step-by-step explanation:

3x+4=9x+3

isolate x

1=6x

1/6=x

6 0
2 years ago
Read 2 more answers
Si el lado de un cuadrado mide 10cm cuanto mide él área del círculo que se encuentra adentro de ese cuadrado
Alex17521 [72]

Answer:

El área del círculo que se encuentra en el cuadrado es de 78.5cm²

Step-by-step explanation:

Para resolver este ejercicio tenemos que pensar que un cuadrado tiene sus 4 lados iguales, por lo que todos sus lados medirán 10cm.

Ahora nos fijamos que necesitamos saber para calcular el área de un circulo

a = área

r = radio

π = 3.14

a = π * r²

como podemos ver no sabemos el valor del radio

como el circulo toca con los 4 lados del cuadrado sabemos que su radio sera la distancia del centro del cuadrado a cualquiera de los lados.

Entonces tenemos que dividir un lado por 2

10cm/2 = 5cm

El radio del circulo sera 5cm

Ahora que tenemos todos los datos podemos calcular el valor del área

a = 3.14 * (5cm)²

a = 3.14 * 25cm²

a = 78.5cm²

El área del círculo que se encuentra en el cuadrado es de 78.5cm²

8 0
3 years ago
Will mark as brainliest
lapo4ka [179]

Answer:

-1 + 2 = 1

1 + (-2) = -1

-1 - 2 = -3

1 - (-2) = 3

Step-by-step explanation

When you subtract use keep change change

Rule 1 when you add : If the signs are the same add the numbers and take the sign of the bigger number.

Rule 2 when you add : If the signs are different subtract the numbers and take the sign of the bigger number.

I wanted to help you understand and i hope i did that!

8 0
3 years ago
Find limit as x approaches 2 from the left of the quotient of the absolute value of the quantity x minus 2, and the quantity x m
Molodets [167]

Answer:

\lim_{x \to 2^-} \frac{|x-2|}{x-2}=-1.

Step-by-step explanation:

We want to find \lim_{x \to 2^-} \frac{|x-2|}{x-2}.

By definition:

|x-2|=\left \{ {{x-2,\:if\:x\:>\:2} \atop {-(x-2),\:if\:x\:

Since we want to find the Left Hand Limit, we use f(x)=-(x-2)

\implies \lim_{x \to 2^-} \frac{|x-2|}{x-2}=\lim_{x \to 2} \frac{-(x-2)}{x-2}.

\implies \lim_{x \to 2^-} \frac{|x-2|}{x-2}=\lim_{x \to 2} (-1).

The limit of a constant is the constant.

\implies \lim_{x \to 2^-} \frac{|x-2|}{x-2}=-1.

8 0
2 years ago
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