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sergey [27]
3 years ago
14

How do I solve this type of problem? I'm trying to find both missing values. Please explain how to solve this as thoroughly as y

ou can.

Mathematics
1 answer:
goldenfox [79]3 years ago
3 0
Hi there! 

In order to solve, we'll need to use a proportion: 20/a = 21/20. Then, we'll cross-multiply and solve to find a: 21a = 400 | a = 19.05. Next, to find b, we can just use pythagorean theorem: 20^2 + (400/21)^2 = b^2 | b = 27.62.
We are using geometric mean to solve for a, then using pythagorean theorem to solve for b. If you need more help with geometric mean, or would like a complete explanation, please let me know! I'd be happy to provide you with that information.

Hope this helps!! :)
If there's anything else that I can help you with, please let me know!
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Suppose a bag of marbles has 4 green, 2 red, 5 yellow, 1 brown, and 7 blue marbles. What is the probability of picking a green m
Helga [31]

Answer:

1. There are a total of 19 marbles in the bag. The probability of picking a green marble out of them is 4/19 since there are only 4 green ones. The probability of picking a brown marble after replacing what has been initially picked is 1/19. The final probability is the product of the two probabilities and that is 4/361.

2. ?

3. 60%

Step-by-step explanation:

8 0
3 years ago
9×27+2×31-28=n what is the value of n
patriot [66]

(9)(27)+(2)(31)−28=n

Simplify:

(9)(27)+(2)(31)−28=n

243+62+−28=n

(243+62+−28)=n(Combine Like Terms)

277=n

Flip the equation.

n=277

6 0
3 years ago
Solve the proportion
sashaice [31]
0.25 I think not sure
4 0
2 years ago
George and his friends rode motorcycles all day on Saturday. He made a table that showed the number of gallons of gas remaining
salantis [7]

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negative correlation

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his fuel keeps decreasing every time he uses his motorcycle

5 0
2 years ago
If tñ=2ñ+3, find S10​
Allisa [31]

Answer:

S_{10}=280

Step-by-step explanation:

Given that,

t_n=2n+3 ...(1)

We need to find the value of S_{10}.

Put n = 1 to find the first term.

t_1=2(1)+3=5

Put n = 2 to find the second term.

t_2=2(2)+3=7

Put n = 3 to find the third term.

t_3=2(3)+3=9

Put n = 10 to find the tenth term.

t_{10}=2(10)+3=23

It means we need to find the sum of 5,7,9,.....,23.

The formula for the sum of n terms is given by :

S_=\dfrac{n}{2}(a+a_n)

We have, n = 10, a = 5 and a_n=23

So,

S=\dfrac{10}{2}(5+23)\\\\S_{10}=10\times 28\\\\=280

So, the value of S_{10} is equal to 280.

3 0
3 years ago
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