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sergey [27]
3 years ago
14

How do I solve this type of problem? I'm trying to find both missing values. Please explain how to solve this as thoroughly as y

ou can.

Mathematics
1 answer:
goldenfox [79]3 years ago
3 0
Hi there! 

In order to solve, we'll need to use a proportion: 20/a = 21/20. Then, we'll cross-multiply and solve to find a: 21a = 400 | a = 19.05. Next, to find b, we can just use pythagorean theorem: 20^2 + (400/21)^2 = b^2 | b = 27.62.
We are using geometric mean to solve for a, then using pythagorean theorem to solve for b. If you need more help with geometric mean, or would like a complete explanation, please let me know! I'd be happy to provide you with that information.

Hope this helps!! :)
If there's anything else that I can help you with, please let me know!
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The number of cartons of apples sold at a store each day for eight days is shown. 30 , 40 , 51 , 30 , 34 , 20, 30, 45 Determine
nikitadnepr [17]

Answer:

Mean = 35

Median = 0.5(n + 1)th term

Median = 0.5(9) = 4.5th term

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Mode = 30 ( most frequent)

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Mean = 72

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Median = 0.5(9) = 4.5th term

4th + 5term = (72 + 77) /2 = 74.5

Mode = 72 ( most frequent)

Range = (90 - 48) = 42

Step-by-step explanation:

Given :

1.)

Data: 30 , 40 , 51 , 30 , 34 , 20, 30, 45

Rearranged data : 20, 30, 30, 30, 34, 40, 45, 51

Mean = ΣX / n = 280 / 8

Mean = 35

Median = 0.5(n + 1)th term

Median = 0.5(9) = 4.5th term

(30 + 34) /2 = 32

Mode = 30 ( most frequent)

Range = (51 - 20) = 31

2.)

90 , 72 , 48 , 84 , 77 , 72, 50, 83

Rearranged data : 48, 50, 72, 72, 77, 83, 84, 90

Mean (m) = ΣX / n = 576 / 8

Mean = 72

Median = 0.5(n + 1)th term

Median = 0.5(9) = 4.5th term

4th + 5term = (72 + 77) /2 = 74.5

Mode = 72 ( most frequent)

Range = (90 - 48) = 42

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Which of the following expressions are equivalent to x + y-z
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C since y-x are being subtracted and there should be another subtraction but there isnt

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