Answer:
x=8 and y=3 (So, yes!)
Step-by-step explanation:
I will solve your system by substitution.
(You can also solve this system by elimination.)
−x+4y=4;−x+3y=1
Step: Solve −x+4y=4 for x:
−x+4y+−4y=4+−4y(Add -4y to both sides)
−x=−4y+4
-x/-1 = -4y+4/-1 (Divide both sides by -1)
x=4y−4
Step: Substitute 4y−4 for x in −x+3y=1:
−x+3y=1
−(4y−4)+3y=1
−y+4=1(Simplify both sides of the equation)
−y+4+−4=1+−4(Add -4 to both sides)
−y=−3
-y/-1 = -3/-1 (Divide both sides by -1)
y=3
Step: Substitute 3 for y in x=4y−4:
=4y−4
x=(4)(3)−4
x=8(Simplify both sides of the equation)
<u>Answer:</u>
x=8 and y=3
Work: -3p-(-8+4p)
Distribute
-3p+8-4p
Combine
-7p+8
Answer: -7p+8
Hope that helps
Here, y = -15 with x = -20
LCM of 15 & 20 is 60, so divide 15 & 20 from 60,
60/15 = 4 & 60/20 = 3
Now, multiply the results with intial values,
4y = 3x
y = 3/4 x
When y = 12,
x = 12 * 4/3
x = 48 / 3
x = 16
In short, Your Answer would be 16
Hope this helps!
Answer:
Simplify−412+16t+48.h=16t−1633
Step-by-step explanation:
