A positive charge +q= +8.0*10^-8 C with mass m=5.5*10^-10 kg, located at the +V plate, is at rest. If the final speed of the cha
rge is vf=600m/s when it strikes the -Vplate, what is the electric potential V of the plates? A. 24.9 V B. 1240 V C. 1000 V D. 619 V E. 1.03 V
2 answers:
Answer:
B. 1240 V
Explanation:
Given
Initial velocity of the charge, u = 0 m/s
Final velocity of the charge, v = 600 m/s
Magnitude of the charge, q =
mass of the charge, m =
Solution
Gain in mechanical energy = Loss in electric potential energy
Rounding off the answer to closest tens, we get
V = 1240 V
Answer:
Explanation:
As we know that charge moves from higher potential to lower potential
so here change in electrostatic potential energy must be equal to final kinetic energy of the charge
so we will have
so we will have
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