Answer:
Flow Rate = 80 m^3 /hours (Rounded to the nearest whole number)
Explanation:
Given
- Hf = head loss
- f = friction factor
- L = Length of the pipe = 360 m
- V = Flow velocity, m/s
- D = Pipe diameter = 0.12 m
- g = Gravitational acceleration, m/s^2
- Re = Reynolds's Number
- rho = Density =998 kg/m^3
- μ = Viscosity = 0.001 kg/m-s
- Z = Elevation Difference = 60 m
Calculations
Moody friction loss in the pipe = Hf = (f*L*V^2)/(2*D*g)
The energy equation for this system will be,
Hp = Z + Hf
The other three equations to solve the above equations are:
Re = (rho*V*D)/ μ
Flow Rate, Q = V*(pi/4)*D^2
Power = 15000 W = rho*g*Q*Hp
1/f^0.5 = 2*log ((Re*f^0.5)/2.51)
We can iterate the 5 equations to find f and solve them to find the values of:
Re = 235000
f = 0.015
V = 1.97 m/s
And use them to find the flow rate,
Q = V*(pi/4)*D^2
Q = (1.97)*(pi/4)*(0.12)^2 = 0.022 m^3/s = 80 m^3 /hours
Answer: The canyon wall is 850 m away from the person
Explanation:
Well, the speed of sound
in air at
is defined as
, this can be calculated by the following equation:
(1)
Where:
is the Heat capacity ratio for air
is the Universal Gas constant
is the temperature in Kelvin
is the air molar mass

(2)
Now that we know the speed of sound, we can use the following equation to find the distance between the person and the canyon wall:
(3)
Where:
is the distance between the person and the canyon wall
is the time it takes to the sound wave to travel from the person and then go back
Isolating
:
(4)
(5)
Finally:
Answer:
Burning wax
Explanation:
because in burning, wax reacts with oxygen present in the surrounding and forms carbon dioxide and ash
To solve the exercise, the key concept to be addressed is the Mass Center.
The center of mass of an object is measured as,


Our values are given by,







Replacing the values in our previous equation we have,






Therefore the mass of the meter stick is 7.928g
Answer:
m₂ = 3kg
Explanation:
The question wasn't clear about what direction the initial velocity of the second cart was, so I'll assume it was going left at 2.0m/s.
Anyway, this is a conservation of momentum problem. The equation you need to use is the one written in blue. They want you to solve for the mass of the second cart, so do some algebra and rearrange that blue equation in term of m₂.
Now that you have the equation for m₂, plug in all the values given from the question and you'll get 3kg.