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Dvinal [7]
3 years ago
8

URGENT!!!! The coleman family had their bill at a resturant reduced by $7.50 because of a special discount. They left a tip of $

8.90 which was 20% of the reduced amount. Using x to represent the original bill write an algebraic equation and solve it to find the cost of their bill before the discount. SHOW ALL WORK PLEASE.
Mathematics
1 answer:
Alborosie3 years ago
3 0
I believe it is right ($52.00) but this could be wrong sorry

$8.90×20%

$8.90÷.20=44.5

discounted price:$44.5

44.5+$7.50=$52.00

original price without discount:$52.00

hopefully this helped:)|:)|:)|

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Oksanka [162]

Answer:

The error Ben made was writing down 6,550,000 cars rather than 5,650,000 cars in the report.

He can fix it by correcting the wrong numbers.

Step-by-step explanation:

American car produce 5,650,000 cars each year.

When writing a report Ben wrote down that americans produce 6,550,000 cars every year

Therefore the error Ben made in the report was that he mixed the numbers, he ought to have written 5 and 6 as the initial two numbers but rather he wrote the first number as 6 and the second number as 5.

Ben can fix his mistake by correcting the numbers and writing down the correct initial two numbers which are 6 and 5.

Hence, doing this will give him the correct number of cars which is 5,650,000 cars.

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3 years ago
What is the remainder when x^2+ 3 is divided by x - 1?
emmasim [6.3K]

Step-by-step explanation:

x² + 3 / x - 1 = x + 1

- x² - x

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0 x + 3

- x - 1

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the remainder is 4

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3 years ago
6% greater than or less than 48%
elena-s [515]
6% is less than 48%. Due to the reason that 48% is a larger portion.
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If $1,000 is invested at 4% simple interest, how much will the investment be worth after 2 years? Please explain how compound an
Novay_Z [31]
<h3>Answer:</h3>
  • simple interest: $1080.00
  • compounded annually: $1081.60
<h3>Step-by-step explanation:</h3>

<em>Simple Interest</em>

Simple interest is computed on the principal amount only. Each year, 4% of the principal is added to the balance. So, at the end of 2 years, the balance is ...

... $1000 + 0.04×$1000 + 0.04×$1000

... = $1000×(1 + 0.04×2) = $1000×1.08

... = $1080.00

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<em>Comment on the computation</em>

The added interest is the rate (per year) multiplied by the number of years. Here, that is 0.04×2×(principal amount). The formula for the simple interest earned is often seen as ...

... I = Prt . . . . . where I is the amount of interest, P is the principal amount, r is the interest rate for the time period, t is the number of time periods.

The account balance (A) with interest added is ...

... A = P + I = P + Prt

... A = P(1 +rt)

Here, the time period is years, and the rate given is an annual rate.

____

<em>Compound Interest</em>

Compound interest is computed on the <em>account balance</em> at the beginning of the period, not just the <em>principal</em> amount. After the first period, the account balance includes interest earned so far. So, the interest is earning interest. That is why it is called compounded interest.

Here, the balance at the end of the first year is the principal amount plus the interest that has earned:

... $1000 + 0.04×$1000 = $1000×1.04 = $1040.00

The balance at the end of the second year when the interest is compounded is this account balance plus the interest it earns:

... $1040 + 0.04×$1040 = $1040×1.04 = $1081.60

You may notice that the intial principal, $1000, has been multiplied by the factor 1.04 twice. Using exponents, the multiplier for a period of 2 years is 1.04×1.04 = 1.04².

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<em>Comment on the computation</em>

The multiplier of the account balance each year is raised to a power that is the number of years. Here, the account balance at the end of 2 years is (1+0.04)² times the principal amount. A formula that is seen for this is ...

... A = P(1 +r)^t . . . . . where A is the final account balance, P is the principal amount, r is the interest rate for the time period, and t is the number of time periods.

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nasty-shy [4]
Coefficients are the numbers in from with the variable, the constant is just a number and the degree is the exponent.
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