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Nonamiya [84]
2 years ago
14

PLEASE HELP IK THIS ISN'T MATH BUT PLEASE HELP ITS TIMED

Mathematics
1 answer:
snow_lady [41]2 years ago
5 0
The one you have marked is correct.



brainliest? if not, that’s okay. :)
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Adult red wolves vary in length from 137.16 cm to 168.64 cm. Estimate the difference in length between the longest and shortest
Gennadij [26K]
Add the two together and divide the answer by 137.16 add it together
8 0
3 years ago
Solve the simultaneous equations<br> -x + 5y = -7<br> x + y = – 5<br> x = 1<br> y= 0
vodomira [7]

y= -5-x

-x + 5(-5-x) = -7

-x -25-5x =-7

-x-5x = 25 -7

-6x= 18

x = -3

-3 +y = -5

y= -5 +3

=-2

-(-3) + 5(-2)

3 - 10 = -7

5 0
3 years ago
Read 2 more answers
Help please!!! I dont understand these questions<br><br><br>currently attaching photos dont delete
Katyanochek1 [597]

Answer:

  1. b/a
  2. 16a²b²
  3. n¹⁰/(16m⁶)
  4. y⁸/x¹⁰
  5. m⁷n³n/m

Step-by-step explanation:

These problems make use of three rules of exponents:

a^ba^c=a^{b+c}\\\\(a^b)^c=a^{bc}\\\\a^{-b}=\dfrac{1}{a^b} \quad\text{or} \quad a^b=\dfrac{1}{a^{-b}}

In general, you can work the problem by using these rules to compute the exponents of each of the variables (or constants), then arrange the expression so all exponents are positive. (The last problem is slightly different.)

__

1. There are no "a" variables in the numerator, and the denominator "a" has a positive exponent (1), so we can leave it alone. The exponent of "b" is the difference of numerator and denominator exponents, according to the above rules.

\dfrac{b^{-2}}{ab^{-3}}=\dfrac{b^{-2-(-3)}}{a}=\dfrac{b}{a}

__

2. 1 to any power is still 1. The outer exponent can be "distributed" to each of the terms inside parentheses, then exponents can be made positive by shifting from denominator to numerator.

\left(\dfrac{1}{4ab}\right)^{-2}=\dfrac{1}{4^{-2}a^{-2}b^{-2}}=16a^2b^2

__

3. One way to work this one is to simplify the inside of the parentheses before applying the outside exponent.

\left(\dfrac{4mn}{m^{-2}n^6}\right)^{-2}=\left(4m^{1-(-2)}n^{1-6}}\right)^{-2}=\left(4m^3n^{-5}}\right)^{-2}\\\\=4^{-2}m^{-6}n^{10}=\dfrac{n^{10}}{16m^6}

__

4. This works the same way the previous problem does.

\left(\dfrac{x^{-4}y}{x^{-9}y^5}\right)^{-2}=\left(x^{-4-(-9)}y^{1-5}\right)^{-2}=\left(x^{5}y^{-4}\right)^{-2}\\\\=x^{-10}y^{8}=\dfrac{y^8}{x^{10}}

__

5. In this problem, you're only asked to eliminate the one negative exponent. That is done by moving the factor to the numerator, changing the sign of the exponent.

\dfrac{m^7n^3}{mn^{-1}}=\dfrac{m^7n^3n}{m}

3 0
3 years ago
Distribute -2(2x-1)(x+3), i forgot how to use the distributive property to check my work on factoring quadratics.
Gwar [14]
-2(2x-1)(x+3) = ((-2)2x - (-2)(-1))(x+3) = (-4x-2)(x+3) 
3 0
3 years ago
Read 2 more answers
How can you Express 3 3/8 as a fraction ?​
Solnce55 [7]

Answer:

You mean improper fraction?

3 x 8 = 24

24 + 3 = 27

27/8

3 0
3 years ago
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