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3 years ago

PLEASE HELP IK THIS ISN'T MATH BUT PLEASE HELP ITS TIMED

Mathematics

1 answer:

snow_lady [41]3 years ago

5 0

The one you have marked is correct.

brainliest? if not, that’s okay. :)

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What is the answer 2.07 ÷ 0.9

storchak [24]

The answer is 2.3 right.

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3 years ago

Helpppppppppppppppppp

WINSTONCH [101]

X 3 5
Y 6 10

ANSWER #3. .

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3 years ago

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n a jar of coins, the ratio of nickels to dimes is 5:7. If the jar contains 350 dimes, how many nickels are there?

irina1246 [14]

Answer:

250 nickles

Step-by-step explanation:

Nickles and dimes are coins with different currency values. One nickel(N) is equal to 5 cents while one dime(D) is equal to 10 cents. The ratio of nickel:dime is 5:7, to put into the equation it will be:

N/D= 5/7

7N=5D ---> 1st equation

There are 350 dimes, the equation will be:

D=350 ----> 2nd equation

We can find out the number of nickels by substitute the 2nd equation into the first. The calculation will be

7N=5D

N= 5D/7

N=5(350)/7

N= 250

4 0

4 years ago

Naval intelligence reports that 4 enemy vessels in a fleet of 17 are carrying nuclear weapons. If 9 vessels are randomly targete

icang [17]

Answer:

0.7588 = 75.88% probability that more than 1 vessel transporting nuclear weapons was destroyed

Step-by-step explanation:

The vessels are destroyed without replacement, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

In this question:

Fleet of 17 means that $N = 17$

4 are carrying nucleas weapons, which means that $k = 4$

9 are destroyed, which means that $n = 9$

What is the probability that more than 1 vessel transporting nuclear weapons was destroyed?

This is:

$P(X > 1) = 1 - P(X \leq 1)$

In which

$P(X \leq 1) = P(X = 0) + P(X = 1)$

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

$P(X = 0) = h(0,17,9,4) = \frac{C_{4,0}*C_{13,9}}{C_{17,9}} = 0.0294$

$P(X = 1) = h(1,17,9,4) = \frac{C_{4,1}*C_{13,8}}{C_{17,9}} = 0.2118$

Then

$P(X \leq 1) = P(X = 0) + P(X = 1) = 0.0294 + 0.2118 = 0.2412$

$P(X > 1) = 1 - P(X \leq 1) = 1 - 0.2412 = 0.7588$

0.7588 = 75.88% probability that more than 1 vessel transporting nuclear weapons was destroyed

8 0

3 years ago

What is the range? 6 7 8 7 10

jeka94

Range= 4

Range is the highest number minus the lowest number, 10-6=4

4 0

3 years ago

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