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KiRa [710]
3 years ago
7

-2(x+5)=2 is an example of wich property

Mathematics
1 answer:
denpristay [2]3 years ago
5 0
-2(x + 5) = 2  |use distributive property: a(b + c) = ab + ac

-2x - 10 = 2    |add 10 to both sides

-2x = 12    |divide both sides by (-2)

x = -6
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3 0
3 years ago
Peyton has collected 120 aluminum cans for recycling. If 20 cans will fit in each blue plastic bag, how many bags will she need
gogolik [260]

Hi Renee!

--------------------------------------------

We Know:

120 aluminum cans.

20 cans fit in each blue bag.

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Solution:

120 / 20 = 6

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Answer:

She will need 6 bags to carry all the aluminum cans.

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6 0
3 years ago
Please help 16 points
Murljashka [212]
16 because 36 divided by 9 is 4 so you have to multiply the 4 x 4
4 0
3 years ago
Read 2 more answers
What is the measure of angle A?
bogdanovich [222]

Answer:

actual answer is 77.32 !

Step-by-step explanation:


5 0
3 years ago
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Use the surface integral in​ Stokes' Theorem to calculate the circulation of the field Bold Upper F equals x squared Bold i plus
Alinara [238K]

Answer:

The circulation of the field f(x) over curve C is Zero

Step-by-step explanation:

The function f(x)=(x^{2},4x,z^{2}) and curve C is ellipse of equation

16x^{2} + 4y^{2} = 3

Theory: Stokes Theorem is given by:

I= \int \int\limits {{Curl f\cdot \hat{N }} \, dx

Where, Curl f(x) = \left[\begin{array}{ccc}\hat{i}&\hat{j}&\hat{k}\\\frac{∂}{∂x} &\frac{∂}{∂y} &\frac{∂}{∂z} \\F1&F2&F3\end{array}\right]

Also, f(x) = (F1,F2,F3)

\hat{N} = grad(g(x))

Using Stokes Theorem,

Surface is given by g(x) = 16x^{2} + 4y^{2} - 3

Therefore, tex]\hat{N} = grad(g(x))[/tex]

\hat{N} = grad(16x^{2} + 4y^{2} - 3)

\hat{N} = (32x,8y,0)

Now,  f(x)=(x^{2},4x,z^{2})

Curl f(x) = \left[\begin{array}{ccc}\hat{i}&\hat{j}&\hat{k}\\\frac{∂}{∂x} &\frac{∂}{∂y} &\frac{∂}{∂z} \\F1&F2&F3\end{array}\right]

Curl f(x) = \left[\begin{array}{ccc}\hat{i}&\hat{j}&\hat{k}\\\frac{∂}{∂x} &\frac{∂}{∂y} &\frac{∂}{∂z} \\x^{2}&4x&z^{2}\end{array}\right]

Curl f(x) = (0,0,4)

Putting all values in Stokes Theorem,

I= \int \int\limits {Curl f\cdot \hat{N} } \, dx

I= \int \int\limits {(0,0,4)\cdot(32x,8y,0)} \, dx

I= \int \int\limits {(0,0,4)\cdot(32x,8y,0)} \, dx

I=0

Thus, The circulation of the field f(x) over curve C is Zero

3 0
3 years ago
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