3 and 2/5 turns into 17/5
1 and 1/5 turns into 6/5
17+6= 23
23/5 simplifies to 4 and 3/5
The equation for cosine is <span><span><span>cos<span>(x)</span></span>=<span>Adjacent/Hypotenuse
</span></span></span>The inside trig function is <span><span>arccos<span>(<span>3/5</span>)</span></span></span>, which means <span><span><span>cos<span>(x)</span></span>=<span>3/5</span></span></span>. Comparing <span><span><span>cos<span>(x)</span></span>=<span>Adjacent/Hypotenuse</span></span></span> with <span><span><span>cos<span>(x)</span></span>=<span>3/5
</span></span></span>
Find <span><span>Adjacent=3</span></span> and <span><span>Hypotenuse=5.
</span></span>Then, using the Pythagorean theorem, find <span><span>Opposite=?
</span></span>a² = c² - b²
a² = 5² - 3² = 25 - 9 = 16
a = √16 = 4
<span><span>Adjacent=3</span></span><span><span>Opposite=4</span></span><span><span>Hypotenuse=5
</span></span><span>
Plug in the value for sin(x) = opposite/hypotenuse
sin(x) = 4/5 </span>
6x
42/6 = 7 (valid), 18/6 = 3 (valid), 12/6 = 2 (valid)
7, 8, 9, 10, and 11 are all not divisible by 12, and 12 is not divisible by 18, so 6 is the highest number.
Also, each number has at least one x, so you can take one out.
Remaining=
6x (7 + 3x^2 + 2x^3)
Answer:
6, 11, 16, 21
Step-by-step explanation:
To obtain the first 4 terms add the common difference 5 to the previous term, that is
a₁ = 6
a₂ = a₁ + 5 = 6 + 5 = 11
a₃ = a₂ + 5 = 11 + 5 = 16
a₄ = a₃ + 5 = 16 + 5 = 21
