A. The population would be 120
You would find 20 percent of 100
To do that, you do 100× 0.2 and add that to 100
B. The population doubles
10×2= 20
20×2= 40, not 30
hope this helps!
1.x^2 +6x - 4 = 6x
X^2 + 6x -4 - 6x = 0
X^2 - 4 = 0
By difference of two squares :
X^2 - 4 = 0 can be written as (x-2) (x+2) = 0
(X-2)=0 therefore x= 2
(X+2)=0 therefore x= -2
2. X^2 - 8x = -6x
X^2 -8x + 6x = 0
X^2 - 2x = 0
X(X-2) = 0
X= 0, X= 2
Answer:
A= -u²n²t²s²arme²
Step-by-step explanation:
Evaluate m, then set it equal to 15.
=15
Evaluate s, the set it equal to 2.
=2
Simplify unitsareminutes.
−u²n²t²s²arme²
List all the solutions.
BN•N=BN²
m=15 ==15
s=2 2==2
Answer:
Hi, there the answer is C. y=33/2x+425
I tried uploading a picture on how I got, but it keep saying I'm using offensive word, which I didn't but trust me the answer is right
Step-by-step explanation:
Answer:
The height of the triangle is 7cm and the base is 16cm
Step-by-step explanation:
First of all we have to know the formula to calculate area of a triangle
a = area = 56
b = base
h = heigth
a = (b * h)/2
we replace the known values and we make 2 equations
56cm² = (b * h)/2
b = h + 9cm
we replace b by (h + 9cm) in the first equation
56cm² = (h + 9cm * h)/2
56cm² * 2 = h² + 9h
0 = h² + 9h - 112cm²
we use bhaskara formula:
(-b (±) √
(b² - 4ac) ) / 2a
we replace with the known values
h = (-9 (±) √
(9² - 4*1*(-112) ) ) / 2*1
h = (-9 (±) √
(81 + 448) ) ) / 2
h = (-9 (±) √529) /2
h = (-9 (±) 23)/2
h1 = (-9 + 23) / 2
h1 = 14 / 2
h1 = 7
h2 = (-9 - 23) / 2
h2 = -32 / 2
h2 = -16
The height of the triangle is 7cm and the base is 16cm
