For this case, the first thing we must do is define a variable.
We have then:
x: total sales for the week
We now write the equation that models the problem.
We have then:
p (x) = 0.035x + 300
Answer:
a function, p (x), which can be used to determine his pay for the week is:
p (x) = 0.035x + 300
Answer:
Step-by-step explanation:
First, we can transform y = cos(x) to y = 3*cos(x) by stretching the graph vertically by a factor of 3. At x = 0, the y value would now be 3 * 1 = 3 instead of 1 (the stretching would cause all new y-values to be 3 times their original values for any given x).
Now transforming y = 3*cos(x) to y = 3*cos(10*x) will stretch the graph horizontally by a factor of 10 (for any given y value, the new x value corresponding to it is 10 times the original x value).
Finally, to transform y = 3*cos(10*x) to y = 3*cos(10(x-pi)), shift the graph to the right by pi.
Answer:
the probability that the graduate program will have enough funding for all student that join the program is 0.3653 (36.53%)
Step-by-step explanation:
since each student is independent on others the random variable X= x students of 45 applicants will join the program has a binomial probability distribution
P(X=x)= n!/[(n-x)!*x!]*p^x*(1-p)^x
where
n= total number of students= 45
p= probability that a student join the program= 0.7
x= number of students that join the program
then in order to have enough funding x should not surpass 30 students , then
P(X≤30)= ∑P(X) for x from 1 to 30 = F(30)
where F(30) is the cumulative probability distribution
then from binomial probability tables
P(X≤30)= F(30)= 0.3653 (36.53%)
therefore the probability that the graduate program will have enough funding for all student that join the program is 0.3653 (36.53%)
