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Zinaida [17]
3 years ago
10

Colocar los paréntesis adecuadamente para que el resultado sea correcto

Mathematics
2 answers:
dlinn [17]3 years ago
4 0

a.

(2+3)×6=30

b.

12×(7+8)=180

c.

15×(2+3×7)=345

zysi [14]3 years ago
3 0

Answer:

(2+3) x 6 =30

12 x (7+8) = 180

15x (2+(3x7)) = 345

Step-by-step explanation:

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2 years ago
Evaluate the function at the indicated values if possible. If an indicated value is not in the​ domain, say so.
goldfiish [28.3K]

Answer:

f(-7)=0.

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f(3) doesn't exist because 3 isn't in the domain of the function.

Step-by-step explanation:

f(x)=\frac{x+7}{x^2-9} is the given function.

We are asked to find:

f(-7)

f(2)

f(3).

f(-7) means to replace x in the expression called f with -7:

Evaluate \frac{x+7}{x^2-9} at x=-7

\frac{(-7)+7}{(-7)^2-9}

\frac{0}{49-9}

\frac{0}{40}

0

So f(-7)=0.

f(2) means to replace x in the expression called f with 2:

Evaluate \frac{x+7}{x^2-9} at x=2

\frac{2+7}{2^2-9}

\frac{9}{4-9}

\frac{9}{-5}

\frac{-9}{5}

So f(2)=-9/5

f(3) means to replace x in the expression called f with 3:

Evaluate \frac{x+7}{x^2-9} at x=3

\frac{3+7}{3^2-9}

\frac{10}{9-9}

\frac{10}{0}

Division by 0 is not allowed so 3 is not in the domain of our function.

5 0
3 years ago
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