Answer:
Step-by-step explanation:
D. 18 1/5 +22 2/5 +40 1/5
-(-22 2/5) and -(-40 1/5) -----> -*- will become +
Answer:
40 problems
Step-by-step explanation:
8 problems : 5 mins
? : 25 mins
8 x 5 = 40
40 problems
hope this helps
braonliest plz?
x
Problem 7)
The answer is choice B. Only graph 2 contains an Euler circuit.
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To have a Euler circuit, each vertex must have an even number of paths connecting to it. This does not happen with graph 1 since vertex A and vertex D have an odd number of vertices (3 each). The odd vertex count makes it impossible to travel back to the starting point, while making sure to only use each edge one time only.
With graph 2, each vertex has exactly two edges attached to it. So an Euler circuit is possible here.
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Problem 8)
The answer is choice B) 5
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Work Shown:
abc base 2 = (a*2^2 + b*2^1 + c*2^0) base 10
101 base 2 = (1*2^2 + 0*2^1 + 1*2^0) base 10
101 base 2 = (1*4 + 0*2 + 1*1) base 10
101 base 2 = (4 + 0 + 1) base 10
101 base 2 = 5 base 10
Answer:
the difference is 10. I hope this helps
Answer:
Remember that a triangle's area is bh/2, where
b = base
h = height
So. You start with a triangle of base b and height h, add 2 to the height, and get a triangle of area 82.5.
b(h+2)/2 = 82.5
b(h+2) = 165
What you want to do from here is test the b and h from the choices given, and figure out which b and h satisfy this.
(a) If b=13 and h=15, b(h+2) = 221 nope.
(b) If b=9 and h=11, b(h+2) = 117 nope.
(c) If b=11 and h=13, b(h+2) = 165 that's it!
Step-by-step explanation:
