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kumpel [21]
3 years ago
10

Plzzz help am stuck

Mathematics
1 answer:
ANEK [815]3 years ago
4 0
The problem on the is 3 and the problem on the right is 20.
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Equation in slope-intercept form:
Jobisdone [24]

Answer:

y = -x + 3

Step-by-step explanation:

Find the slope using the formula [ y2-y1/x2-x1 ]. We can use the points (0, 3) and (3, 0) to solve.

0-3/3-0

-3/3

-1

From the graph, the y-intercept is (0, 3). Input all the data we know into the slope intercept form expression [ y = mx + b ].

y = -x + 3

Best of Luck!

5 0
3 years ago
In the function y=4x^2-5, what effect does the number -5 have on the graph, as compared to the graph of y=x^2
kati45 [8]
It moves the graph 5 steps downwards on the y axis.
3 0
4 years ago
Write an equation that is perpendicular to y=3/5x-1 and passes through the point (9,14)
Leokris [45]

Answer:

y=(-5/3)x+29

Step-by-step explanation:

we will use the base formula y=mx+b

In order to be perpendicular, the slope must be the flipped fraction and have the opposite sign, so our m is (-5/3)

y=(-5/3)x+b

You can plug in the (9,14) point in order to find the b

14=(-5/3)(9)+b

14=(-45/3)+b

14=(-15)+b

14+15=b

29=b

and so altogether our equation is y=(-5/3)x+29

8 0
3 years ago
Explain how to estimate the lateral area of a right cone with radius 5 cm and slant height 6 cm. Is your estimate an underestima
Iteru [2.4K]

Answer:

The answer in the procedure

Step-by-step explanation:

we know that

The lateral area of a cone is equal to

LA=\pi rl

where

r is the radius of the base

l is the slant height

we have

r=5\ cm

l=6\ cm

assume \pi =3.14

substitute the values

LA=(3.14)(5)(6)=94.2\ cm^{2}

This value is an underestimate, because the assumed pi value is less than the real value

assumed value \pi =3.14

real value \pi =3.1415926536...

8 0
3 years ago
If f(x) = -x^2 + 6x - 1 and g(x) = 3x^2 - 4x - 1, find (f + g)(x).
Alenkinab [10]

f(x)=-x^2+6x-1 \\g(x)=3x^2-4x-1 \\f(x)+g(x)=-x^2+6x-1+3x^2-4x-1=\boxed{2x^2+2x-2}

The answer is A.

Hope this helps.

r3t40

5 0
3 years ago
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