We're going to "cut" the repeating part here in a few steps. First, we're going to put the number in a variable:

Next, to get rid of the negative, we can multiply either side by -1 to get

Now, we won't actually use this -x directly; instead, we want to create two new values, one by multiplying either side by 10:

and the other by multiplying either side by 1000:

Next, we can get rid of the repeated part of the number by subtracting -10x from -1000x:

And finally, we can divide either side of the equation by -990 to find that

Answer:
Step-by-step explanation:
"Find the values of x that satisfy 3x - 2x^2 = 7." Please do not use " × " to represent a variable; " × " is an operator, the "multiply" operator.
Rearrange these three terms in descending order by powers of x:
-2x^2 + 3x - 7 = 0. Here the coefficients are a = -2, b = 3 and c = -7, and so the discriminant of this quadratic is b^2-4ac, or 9 - 4(-2)(-7), or 9 - 56, or -47.
Because the discriminant is negative, we'll have two different complex roots here. The quadratic formula becomes
-3 ± i√47 -3 ± i√47
x = ----------------- = -------------------
2(-2) -4