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3 years ago

WILL GIVE BRAINLIEST PLZ ANSWER ASAP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!11

Mathematics

2 answers:

Alexxx [7]3 years ago

6 0

The congruence theorem is ASA.If you look at the diagram, angle X and angle Z are both right angles, or 90 degrees. This means that these two angles are congruent. Then, segment SZ and segment SX have that line in them, which means that they are congruent. Finally, angle WSX and angle YSZ are vertical angles, meaning that they are also congruent. Since the segments SZ and SX are between the two congruent angles of the triangles, the theorem is ASA.

max2010maxim [7]3 years ago

3 0

<X = <Z

SX = SZ

<WSX = <ZSY

answer : ASA

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Si 2/3 de los 84 pasajeros de un bus de Transmilenio son hombres, ¿cuántas

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Answer:

Step-by-step explanation:

Aquí, tenemos 2/3 como hombres.

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Entonces 1/3 de 84 son mujeres Por lo tanto, el número de mujeres es 1/3 * 84 = 28

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3 years ago

Which of the following is equal to 7 1/3?

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Step-by-step explanation:

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5 0

3 years ago

Read 2 more answers

The internal height of a rectangular box is 10.5cm.The thickness of the bottom is 3/5cm and the thickness of the top is 1cm.What

omeli [17]

The addition is one of the four fundamental mathematical operations, the others being subtraction, multiplication, and division. The external height of the box is 12.1 cm.

<h3>What is Addition?</h3>

The addition is one of the four fundamental mathematical operations, the others being subtraction, multiplication, and division. When two whole numbers are added together, the total quantity or sum of those values is obtained.

Given that the internal height of a rectangular box is 10.5cm. The thickness of the bottom is 3/5cm and the thickness of the top is 1cm. Therefore, the external height of the rectangular box is,

Height of rectangular box

= Thickness of bottom + Internal height of the box + Thickness of the top

= 3/5 cm + 10.5 cm + 1 cm

= 0.6cm + 10.5cm + 1cm

= 12.1 cm

Hence, the external height of the box is 12.1 cm.

Learn more about Addition here:

brainly.com/question/14092461

#SPJ1

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2 years ago

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chubhunter [2.5K]

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2 years ago

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Let f be defined by the function f(x) = 1/(x^2+9)

riadik2000 [5.3K]

(a)

$\displaystyle\int_3^\infty \frac{\mathrm dx}{x^2+9}=\lim_{b\to\infty}\int_{x=3}^{x=b}\frac{\mathrm dx}{x^2+9}$

Substitute x = 3 tan(t ) and dx = 3 sec²(t ) dt :

$\displaystyle\lim_{b\to\infty}\int_{t=\arctan(1)}^{t=\arctan\left(\frac b3\right)}\frac{3\sec^2(t)}{(3\tan(t))^2+9}\,\mathrm dt=\frac13\lim_{b\to\infty}\int_{t=\arctan(1)}^{t=\arctan\left(\frac b3\right)}\mathrm dt$

$=\displaystyle \frac13 \lim_{b\to\infty}\left(\arctan\left(\frac b3\right)-\arctan(1)\right)=\boxed{\dfrac\pi{12}}$

(b) The series

$\displaystyle \sum_{n=3}^\infty \frac1{n^2+9}$

converges by comparison to the convergent p-series,

$\displaystyle\sum_{n=3}^\infty\frac1{n^2}$

$\displaystyle \sum_{n=1}^\infty \frac{(-1)^n (n^2+9)}{e^n}$

converges absolutely, since

$\displaystyle \sum_{n=1}^\infty \left|\frac{(-1)^n (n^2+9)}{e^n}\right|=\sum_{n=1}^\infty \frac{n^2+9}{e^n} < \sum_{n=1}^\infty \frac{n^2}{e^n} < \sum_{n=1}^\infty \frac1{e^n}=\frac1{e-1}$

That is, ∑ (-1)ⁿ (n ² + 9)/eⁿ converges absolutely because ∑ |(-1)ⁿ (n ² + 9)/eⁿ| = ∑ (n ² + 9)/eⁿ in turn converges by comparison to a geometric series.

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3 years ago