A volume of 60.0 mL of a 0.120 M HNO3 solution is titrated with 0.840 M KOH. Calculate the volume of KOH required to reach the e
1 answer:
Answer: 8.57 ml of KOH is required to reach the equivalence point.
Explanation:
To calculate the volume of acid, we use the equation given by neutralization reaction:
where,
are the n-factor, molarity and volume of acid which is
are the n-factor, molarity and volume of base which is KOH.
We are given:
Putting values in above equation, we get:
Thus 8.57 ml of KOH is required to reach the equivalence point.
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I have attached a periodic table to allow you to further understand my answer. We know elements are categorized in groups of Metals, Nonmetals, and metalloids. Let’s analyze each element. Sulfur is a nonmetal which mean it does not conduct well and does not have a good appearance, the same applies to all the other non metals on this list, including sulfur and helium. Copper is our only answer in which it fits and electricity can pass through/conduct easily. So our answer is copper. I hope this helps you with your assignment.