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Juliette [100K]
4 years ago
14

A volume of 60.0 mL of a 0.120 M HNO3 solution is titrated with 0.840 M KOH. Calculate the volume of KOH required to reach the e

quivalence point.
Chemistry
1 answer:
german4 years ago
8 0

Answer: 8.57 ml of KOH is required to reach the equivalence point.

Explanation:

To calculate the volume of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is HNO_3

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is KOH.

We are given:

n_1=1\\M_1=0.120M\\V_1=60.0mL\\n_2=1\\M_2=0.840M\\V_2=?

Putting values in above equation, we get:

1\times 0.120\times 60.0=1\times 0.840\times V_2\\\\V_2=8.57mL

Thus 8.57 ml of KOH is required to reach the equivalence point.

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