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The number of mole of oxygen gas, O₂ in the cylinder given the data is 0.5 mole
<h3>Description of mole </h3>The mole of a substance is related to it's mass and molar mass according to the following equation:
Mole = mass / molar mass
<h3>How to determine the mole of O₂</h3>From the question given, the following data were obtained:
- Mass of O₂ = 16 g g
- Molar mass of O₂ = 32 g/mol
- Mole of O₂ =?
Mole = mass / molar mass
Mole of O₂ = 16 / 32
Mole of O₂ = 0.5 mole
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A chemist must prepare 0.200 L of 1.00 M aqueous silver nitrate working solution. He'll do this by pouring out 1.82 mol/L aqueous silver nitrate stock solution into a graduated cylinder and diluting it with distilled water. How many mL of the silver nitrate stock solution should the chemist pour out?
Answer: 0.110 L
Explanation:
According to the dilution law,
where,
= molarity of stock silver nitrate solution = 1.82 M
= volume of stock silver nitrate solution = ?
= molarity of diluted silver nitrate solution = 1.00 M
= volume of diluted silver nitrate solution = 0.200 L
Putting in the values we get:
Therefore, volume of silver nitrate stock solution required is 0.110 L