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AveGali [126]
3 years ago
9

Raymond purchased a package of ground beef at a cost of $1.98 per pound. If, for the same amount of money, Raymond could have pu

rchased a piece of steak that weighed 40 percent less than the package of ground beef, what was the cost per pound of the steak?A. $4.95B. $4.20C. $3.60D. $3.30E. $3.10
Mathematics
1 answer:
Firlakuza [10]3 years ago
4 0

Answer:

So, the cost per pound of the steak is $3.3.

Step-by-step explanation:

We know that Raymond purchased a package of ground beef at a cost of $1.98 per pound. For the same amount of money, Raymond could have purchased a piece of steak that weighed 40 percent less than the package of ground beef.  

We conclude that 40% is less than one pound,  is equal with 0.6 pound.

We have the following proportion:

0.6:1.98=1:x\\\\0.6x=1.98\\\\x=\frac{1.98}{0.6}\\\\x=3.3\\

So, the cost per pound of the steak is $3.3.

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An animal shelter houses dogs, cats, and rabbits. there are 126 animals at the shelter. of the animals, 1/3 are cats. three four
viva [34]
Given that an animal shelter houses three kinds of animals: dogs, cats and rabbits and it has a total of 126 animals. 1/3 of the animals are cats. This means, 1/3 of 126 is 42. So there are 42 cats. 3/4 of the remaining animals, which is 84 are dogs. So 3/4 of 84 is 63. So there are 63 dogs. 63 dogs plus 42 cats is 105 animals. 126 minus 105 is 21. Therefore, there are only 21 rabbits. Hope this helps.
6 0
3 years ago
From 1960 to 1980 , the consumer price index (cpi) increased from 29.6 to 82.4. If a frozen chicken pie cost $0.28 in 1960 and t
mojhsa [17]

CPI in 1960 = 29.6

CPI in 1980 = 82.4

Growth (%) in CPI = \frac{\text{CPI in 1980 - CPI in 1960}}{\text{CPI in 1960}} × 100

⇒ Growth (%) in CPI = \frac{82.4-29.6}{29.6} × 100

⇒ Growth (%) in CPI = 178.3783.. %

⇒ Growth (%) in CPI = 178.4%

Now, we know that price of frozen chicken pie in 1960 = $0.28

Also, we know that over 1960 to 1980, frozen chicken pie price grew at the same rate as CPI

Hence, Price of Chicken Pie in 1980 = Price of Chicken Pie in 1960 × (1 + Growth in CPI)

⇒ Price of Chicken Pie in 1980 = 0.28 × (1 + 178.4%)

⇒ Price of Chicken Pie in 1980 = 0.28 + (0.28 × 178.4%)

⇒ Price of Chicken Pie in 1980 = 0.28 + 0.49952

⇒ Price of Chicken Pie in 1980 = 0.28 + 0.50

⇒ Price of Chicken Pie in 1980 = $0.78

Hence, price of chicken pie in 1980 would be ~$0.78

8 0
3 years ago
Read 2 more answers
The prior probabilities for events A1 and A2 are P(A1) = 0.20 and P(A2) = 0.80. It is also known that P(A1 ∩ A2) = 0. Suppose P(
Umnica [9.8K]

Answer:

(a) A_1 and A_2 are indeed mutually-exclusive.

(b) \displaystyle P(A_1\; \cap \; B) = \frac{1}{20}, whereas \displaystyle P(A_2\; \cap \; B) = \frac{1}{25}.

(c) \displaystyle P(B) = \frac{9}{100}.

(d) \displaystyle P(A_1 \; |\; B) \approx \frac{5}{9}, whereas P(A_1 \; |\; B) = \displaystyle \frac{4}{9}

Step-by-step explanation:

<h3>(a)</h3>

P(A_1 \; \cap \; A_2) = 0 means that it is impossible for events A_1 and A_2 to happen at the same time. Therefore, event A_1 and A_2 are mutually-exclusive.

<h3>(b)</h3>

By the definition of conditional probability:

\displaystyle P(B \; | \; A_1) = \frac{P(B \; \cap \; A_1)}{P(B)} = \frac{P(A_1 \; \cap \; B)}{P(B)}.

Rearrange to obtain:

\displaystyle P(A_1 \; \cap \; B) = P(B \; |\; A_1) \cdot  P(A_1) = 0.25 \times 0.20 = \frac{1}{20}.

Similarly:

\displaystyle P(A_2 \; \cap \; B) = P(B \; |\; A_2) \cdot  P(A_2) = 0.80 \times 0.05 = \frac{1}{25}.

<h3>(c)</h3>

Note that:

\begin{aligned}P(A_1 \; \cup \; A_2) &= P(A_1) + P(A_2) - P(A_1 \; \cap \; A_2) = 0.20 + 0.80 = 1\end{aligned}.

In other words, A_1 and A_2 are collectively-exhaustive. Since A_1 and A_2 are collectively-exhaustive and mutually-exclusive at the same time:

\displaystyle P(B) = P(B \; \cap \; A_1) + P(B \; \cap \; A_2) = \frac{1}{20} + \frac{1}{25} = \frac{9}{100}.

<h3>(d)</h3>

By Bayes' Theorem:

\begin{aligned} P(A_1 \; |\; B) &= \frac{P(B \; | \; A_1) \cdot P(A_1)}{P(B)} \\ &= \frac{0.25 \times 0.20}{9/100} = \frac{0.05 \times 100}{9} = \frac{5}{9}\end{aligned}.

Similarly:

\begin{aligned} P(A_2 \; |\; B) &= \frac{P(B \; | \; A_2) \cdot P(A_2)}{P(B)} \\ &= \frac{0.05 \times 0.80}{9/100} = \frac{0.04 \times 100}{9} = \frac{4}{9}\end{aligned}.

6 0
3 years ago
Please help me out!​
IgorLugansk [536]

w=7.5

Step-by-step explanation:

area of triangle is 6x5=30/2= 15 and then you divide 15 which 7.5

8 0
3 years ago
Did I do it right??? Please respond.
Sedaia [141]

Fraid not.  This time, you did it left.

The tool to use is "Vertical" angles are equal. (They don't add up to 180 degrees.)

3y + 120 = 5y + 100

(you should fill in the missing steps)

y = 10°

The upper/lower pair of vertical angles are both 150°.

.

2x = 6x - 60

(you should fill in the missing steps)

x = 15°

The left/right pair of vertical angles are both 30°.

It's any two angles NEXT TO each other that add up to 180°.

Notice here that (150° + 30°) = 180° .

8 0
3 years ago
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