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3 years ago

Find the interior angles of a regular polygon which has 6, 10 and 20 sides

Mathematics

1 answer:

andrew-mc [135]3 years ago

4 0

Answer:

(6)=120°

(10)=72°

(20)=36°

Step-by-step explanation:

(n-2)×180°

(6-2)×180°=720°

6÷720°=120°

10÷720°=72°

20÷720°=36°

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A manufacturer of pickup trucks is required to recall all the trucks manufactured in a given year for the repair of possible def

Crank

Answer: 2%

Step-by-step explanation:

Let A be the event of having defective steering and B be the vent of having defective brake linings.

Given: P(A) = 0.03 P(B) = 0.05

P(neither A nor B ) = 0.94

Using formula: P(either A nor B) = 1- P(neither A nor B )

= 1-0.94

i.e. P(either A nor B) =0.06

Using formula:P(A and B) = P(A)+P(B)-P(either A or B)

P(A and B) =0.03+0.05-0.06

= 0.02

Hence, the percentage of the trucks have both defects = 2%

8 0

3 years ago

Determine whether the events are independent or dependent: selecting a jellybean and then choosing a second jellybean without re

soldi70 [24.7K]

Dependent, because you're changing the probability

6 0

3 years ago

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Anni [7]

The true statement about the diagram is (a) IJ ≅ JG

<h3>How to determine the true statement?</h3>

From the question, we understand that:

KH bisects line IG at point J

This means that:

Line segment IG is divided into two equal parts, and point J is the middle

So, we have:

IJ ≅ JG

Hence, the true statement about the diagram is (a) IJ ≅ JG

Read more about perpendicular bisector at:

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8 0

2 years ago

Please help I’m stuck.

Sholpan [36]

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7 0

3 years ago

The sum of the first two terms of an infinite GP is 6 and each term is 5 times the sum of the succeeding termsthen the second te

kozerog [31]

Answer:

$\dfrac{6}{7}$ .

Step-by-step explanation:

It is given that the sum of first two terms of an infinite GP is 6.

nth term of a GP is

$a_n=ar^{n-1}$

$a+ar=6$ ...(1)

Each term is 5 times the sum of the succeeding terms.

$a_n=5(a_{n+1}+a_{n+2}+...+\infty)$

$ar^{n-1}=5(ar^n+ar^{n+1}+...+\infty)$

$ar^{n-1}=5ar^n(1+r+r^2+...+\infty)$

Divide both sides by a.

$r^{n-1}=5r^n(\dfrac{1}{1-r})$ $[\text{Sum of infinite GP}=\dfrac{a}{1-r}]$

$\dfrac{r^n}{r}=\dfrac{5r^n}{1-r}$

$\dfrac{1}{r}=\dfrac{5}{1-r}$

$1-r=5r$

$1=6r$

$\dfrac{1}{6}=r$

The common ratio is 1/6.

Put r=1/6 in (1).

$a+a(\dfrac{1}{6})=6$

$6a+a=36$

$7a=36$

$a=\dfrac{36}{7}$

Second term $ar=\dfrac{36}{7}\times \dfrac{1}{6}=\dfrac{6}{7}$

Therefore, the second term is $\dfrac{6}{7}$ .

4 0

3 years ago

Find the interior angles of a regular polygon which has 6, 10 and 20 sides​

Find the interior angles of a regular polygon which has 6, 10 and 20 sides