All categories

3 years ago

Find the interior angles of a regular polygon which has 6, 10 and 20 sides

Mathematics

1 answer:

andrew-mc [135]3 years ago

4 0

Answer:

(6)=120°

(10)=72°

(20)=36°

Step-by-step explanation:

(n-2)×180°

(6-2)×180°=720°

6÷720°=120°

10÷720°=72°

20÷720°=36°

You might be interested in

-2 (3a – 2) = 1/3(7 – 3a)

ahrayia [7]

Answer:

i have no idea. But i will answer because i'm still learning.

Step-by-step explanation:

-2 (3a – 2) = 1/3(7 – 3a)

is whats the question

ok its i'm guessing -2 (3a – 2) = 1/3(7 – 3a)

-2.15384615385

Hope this helps ;)

7 0

3 years ago

Find the circumference of a circle with diameter 8 meters

uysha [10]

The answer is going to 25.13

6 0

3 years ago

Read 2 more answers

Weights of the vegetables in a field are normally distributed. From a sample Carl Cornfield determines the mean weight of a box

pantera1 [17]

To find the z-score for a weight of 196 oz., use

$z=\frac{x-\mu}{\sigma}=\frac{196-180}{8}=\frac{16}{8}=2$

A table for the cumulative distribution function for the normal distribution (see picture) gives the area 0.9772 BELOW the z-score z = 2. Carl is wondering about the percentage of boxes with weights ABOVE z = 2. The total area under the normal curve is 1, so subtract .9772 from 1.0000.

1.0000 - .9772 = 0.0228, so about 2.3% of the boxes will weigh more than 196 oz.

7 0

3 years ago

What is the simplified form of 64x^16

Alenkinab [10]

It can be written as √64·√x¹⁶ = 8x⁸, so answer B.

4 0

3 years ago

1. Trapezoid BEAR has a height of 8.5 centimeters and parallel bases that measure 6.5 centimeters and 11.5 centimeters. To the n

e-lub [12.9K]

<h3>Given</h3>

1) Trapezoid BEAR with bases 11.5 and 6.5 and height 8.5, all in cm.

2) Regular pentagon PENTA with side lengths 9 m

The area of each figure, rounded to the nearest integer

<h3>Solution</h3>

1) The area of a trapezoid is given by

... A = (1/2)(b1 +b2)h

... A = (1/2)(11.5 +6.5)·(8.5) = 76.5 ≈ 77

The area of BEAR is about 77 cm².

2) The conventional formula for the area of a regular polygon makes use of its perimeter and the length of the apothem. For an n-sided polygon with side length s, the perimeter is p = n·s. The length of the apothem is found using trigonometry to be a = (s/2)/tan(180°/n). Then the area is ...

... A = (1/2)ap

... A = (1/2)(s/(2tan(180°/n)))(ns)

... A = (n/4)s²/tan(180°/n)

We have a polygon with s=9 and n=5, so its area is

... A = (5/4)·9²/tan(36°) ≈ 139.36

The area of PENTA is about 139 m².

6 0

3 years ago

Find the interior angles of a regular polygon which has 6, 10 and 20 sides​

Find the interior angles of a regular polygon which has 6, 10 and 20 sides