Question

A random variable X follows the continuous uniform distribution with a lower bound of −4 and an upper bound of 18. a. What is the height of the density function f(x)

Answer 1

Answer:

Height of density function is equal to $\dfrac{1}{22}$.

Step-by-step explanation:

Given that

Lower bound= -4 and upper bound=18 and we need to find height of density function.

We know that height ofProbability density function given as

$Height =\dfrac{1}{Upper\ bound -lower\ bound}$

Now by putting the values in the above formula we will get

$Height =\dfrac{1}{18 -(-4)}$

$Height =\dfrac{1}{22}$

So height of density function is equal to $\dfrac{1}{22}$.

Answer 2

Answer:

The  height of the density function is $\frac{1}{22}$

Step-by-step explanation:

Given : A random variable X follows the continuous uniform distribution with a lower bound of −4 and an upper bound of 18.

To find : What is the height of the density function f(x)?

Solution :

According to question,

The height of the density function is given by,

$f(X)=\frac{1}{b-a}$

Where, a is the lower bound a=-4

b is the upper bound b=18

Substitute the value in the formula,

$f(X)=\frac{1}{18-(-4)}$

$f(X)=\frac{1}{18+4}$

$f(X)=\frac{1}{22}$

Therefore, The  height of the density function is $\frac{1}{22}$