Ask question

Ask question

All categories

3 years ago

11

Rek has a rope 135 feet long. He cuts it into 3 pieces. The 2nd piece is twice as long as the 1st piece. The 3rd piece is 3 time

s as long as the 1st piece. How long is the longest piece of rope?
Create the equations.

1 answer:

AnnyKZ [126]3 years ago

3 0

(2*3*1)=6

135/6=22.5

1st = 22.5 ft

2nd= 45 ft

3rd = 67.5 ft

add it up and you get 135 feet

You might be interested in

how long will it take b and c to equal the same if b starts with 30,000 with an raise of 2400 and c starts with 36000 with a rai

Rufina [12.5K]

The easiest way is to make equations y=2400x+30000 and y=2000+36000
and then put that in the calculator and go to table and the point they intersect at is (15,66000)

3 0

3 years ago

Solve the equation.<br><br> 3(k−6)=15

Natali [406]

Answer:

K = 11

Step-by-step explanation:

3(k - 6) = 15

3k - 18 = 15

3k = 15 + 18

3k = 33

K = 33/3

K = 11

Thus, the value of K is 11

8 0

2 years ago

A point whose x cordinate is zero will lie on options are x-axis ,y-axis and orgin

kenny6666 [7]

Answer:

A point whose x coordinate is zero and y-coordinate is non-zero will lie on the y-axis.

7 0

3 years ago

A survey of 90 men found that an average amount spent on St. Patrick's day of $55 with a standard deviation of $18. A similar su

dem82 [27]

Answer:

The value of the test statistic is 4.70.

Step-by-step explanation:

The hypothesis for this test can be defined as follows:

<em>H</em>₀: Men do not spend more than women on St. Patrick's day, i.e. μ₁ = μ₂.

<em>H</em>ₐ: Men spend more than women on St. Patrick's day, i.e. μ₁ > μ₂.

The population standard deviations are not known.

So a <em>t</em>-distribution will be used to perform the test.

The test statistic for the test of difference between mean is:

$t=\frac{\bar x_{1}-\bar x_{2}}{\sqrt{\frac{s^{2}_{1}}{n_{1}}+\frac{s^{2}_{2}}{n_{2}}} }$

Given:

$\bar x_{1}=55\\s_{1}=18\\n_{1}=90\\\bar x_{1}=44\\s_{1}=16\\n_{1}=86$

Compute the value of the test statistic as follows:

$t=\frac{\bar x_{1}-\bar x_{2}}{\sqrt{\frac{s^{2}_{1}}{n_{1}}+\frac{s^{2}_{2}}{n_{2}}} }=\frac{55-44}{\sqrt{\frac{15^{2}}{90}+\frac{16^{2}}{86} }}=4.70$

Thus, the value of the test statistic is 4.70.

7 0

3 years ago

What is the Greatest Common Factor for 18;45

ira [324]

The GCF for 18 and 45 is 9.

3 0

2 years ago